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a_sh-v [17]
3 years ago
13

13. Identify the y-intercept and the slope for each equation.

Mathematics
1 answer:
mihalych1998 [28]3 years ago
5 0

Answer:

For a )    y = 6x - 3

slope = m = 6\\y-intercept = c = -3\\

For b )     y = -2x - 10

slope = m = -2\\y-intercept = c = -10\\

For c )    y = -4x + 4

slope = m = -4\\y-intercept = c = 4\\

Step-by-step explanation:

Given:

a. y = 6x - 3

b. y = -2 (x + 5)

   y = -2x - 10

c. y = 4 (-x + 1)

  y = -4x + 4

To Find:

y-intercept and the slope for each equation = ?

Solution:

Slope-intercept Formula is given by

y=mx+c

Where,

m = slope

c = y-intercept

So on comparing the Given equations with the above Equation we get

For a )   y = 6x - 3

slope = m = 6\\y-intercept = c = -3\\

For b )    y = -2x - 10

slope = m = -2\\y-intercept = c = -10\\

For c )    y = -4x + 4

slope = m = -4\\y-intercept = c = 4\\

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vladimir2022 [97]

Answer:

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Step-by-step explanation:

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a^2=b^2+c^2-2bc(cosA)

cos A =b^2+c^2-a^2/2bc

if a= 119,b=94,c=173

cos A=94^2+173^2-119^2/2(94*173)

=8836+29,929-14,161/2(16,262)

=38765-14,161/32,524

=24604/32,524

=0.7564

cos A=0.7564

cos^-1=40.85°.that's for angle A.

Using the same formula

B=31.1°

C=180-(40.85+31.1)

C=180-71.95

C=108.05

Since angle on a straight line is 180

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Also the sum of angles A and B

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1 year ago
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Answer:

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Step-by-step explanation:

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3 years ago
Identify Arithmetic Mean, Geometric Mean and Harmonic Mean from the following averages: 56.4, 59.8 and 55.8
photoshop1234 [79]
If you would like to calculate the arithmetic mean, geometric mean, and harmonic mean from the following averages, you can calculate this using the following steps:

averages: 56.4, 59.8, 55.8
the number of values: 3

arithmetic mean:
(56.4 + 59.8 + 55.8) / 3 = 57.33

geometric mean:
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Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

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julsineya [31]

Answer:

if it's a rectangular pyramid a rectangle

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