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lara31 [8.8K]
3 years ago
9

Find the quotient of the quantity negative 5 times x to the 3rd power plus 20 times x to the 2nd power minus 25 times x all over

negative 5 times x.

Mathematics
2 answers:
Alona [7]3 years ago
8 0
Negative x squared minus 4 x plus 5
GalinKa [24]3 years ago
8 0

Answer:

Option 2. (x²- 4x + 5) is the quotient.

Step-by-step explanation:

We have to find the quotient of \frac{-5x^{3} + 20x^{2} -25x}{-5x}.

Now we will factorize numerator as

(-5x³ + 20x² -25x) = -(5x³ - 20x² +25x) = -5x(x² - 4x + 5)

Now we can easily divide this term by the term given in the denominator.

= -5x(x² - 4x +5)/(-5x)

Therefore the quotient will be (x²- 4x + 5).

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Use graphing to find the solutions to the system of equations.
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Read 2 more answers
If f(x) = 4(3x - 5), find f-1(x)
deff fn [24]

Answer:

f^{-1}(x) =  \frac{1}{12}(x+20)

Step-by-step explanation:

Given: f(x) = 4(3x - 5)

Is required to find f⁻¹(x)

f(x) = y = 4(3x - 5)

∴ y = 4 * 3x - 4 * 5

∴ y = 12x - 20 ⇒ add 20 to both sides

∴ y + 20 = 12x ⇒ divide both sides by 12

∴ \frac{1}{12} (y+20) = x

Replace the places of x and y.

∴ y=\frac{1}{12} (x+20)

∴ f^{-1}(x) =  \frac{1}{12}(x+20)

7 0
3 years ago
In right triangle PQR , PQ=12 cm and QR=5cm .What is cos R?
Juliette [100K]

Answer:

cosR = \frac{5}{13}

Step-by-step explanation:

assuming the right triangle has ∠ Q = 90° with legs 5 and 12

then this is a 5- 12- 13 right triangle with hypotenuse PR = 13 cm

then

cosR = \frac{adjacent}{hypotenuse} = \frac{QR}{PR} = \frac{5}{13}

7 0
2 years ago
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