Answer: d. incremental backup
Explanation:
In incremental backup it copies only the files that have changed since the last full backup. It does not backup all the files just like the full backup. it however backup those copies into the system which has changed since the last backup.
In doing so it just increases the efficiency and performance of the backup procedure. This process is basically preferred when the amount of file to be backup is huge and there is not enough time to do a full backup.
Increment backup also use less disk space.
Cloud backup uses most increment backup for its application.
Hi there!
Many certificates (and usually most certificates) are in the landscape page orientation.
Hope this helps!
Either your screen isnt plugged in and synced properly or you have a problem in the automatic boot system
Solution :
#include
#include
#include
//Converts
to binary string.
* hexadecimal
Binary(char* hexdec)
{
long
= 0;
char *string =
(sizeof(char) * 9);
while (hexdec[i]) {
//Simply assign binary string for each hex char.
switch (hexdec[i]) {
strcat(string, "0000");
break;
strcat(string, "0001");
break;
strcat(string, "0010");
break;
strcat(string, "0011");
break;
strcat(string, "0100");
break;
strcat(string, "0101");
break;
strcat(string, "0110");
break;
strcat(string, "0111");
break;
strcat(string, "1000");
break;
strcat(string, "1001");
break;
case 'A':
case 'a':
strcat(string, "1010");
break;
case 'B':
case 'b':
strcat(string, "1011");
break;
case 'C':
case 'c':
strcat(string, "1100");
break;
case 'D':
case 'd':
strcat(string, "1101");
break;
case 'E':
case 'e':
strcat(string, "1110");
break;
case 'F':
case 'f':
strcat(string, "1111");
break;
default:
printf("\nInvalid hexadecimal digit %c",
hexdec[i]);
string="-1" ;
}
i++;
}
return string;
}
int main()
{ //Take 2 strings
char *str1 =hexadecimalToBinary("FA") ;
char *str2 =hexadecimalToBinary("12") ;
//Input 2 numbers p and n.
int p,n;
scanf("%d",&p);
scanf("%d",&n);
//keep j as length of str2
int j=strlen(str2),i;
//Now replace n digits after p of str1
for(i=0;i<n;i++){
str1[p+i]=str2[j-1-i];
}
//Now, i have used c library strtol
long ans = strtol(str1, NULL, 2);
//print result.
printf("%lx",ans);
return 0;
}
Standing for an exceptional performance would be normal "acceptable" in both scenarios.