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3 years ago

6

If $41 is invested in an account that compounds interest annually at 9.4%, what would the balance be in 5 years rounded to the n

earest cent?

1 answer:

mel-nik [20]3 years ago

4 0

A=41×(1+0.094)^(5)
A=64.25

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First question, thanks. I believe there should be 3 answers

zysi [14]

Given: The following functions

$A)cos^2\theta=sin^2\theta-1$ $B)sin\theta=\frac{1}{csc\theta}$ $\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

$\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}$

B

$\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}$

C

$\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}$

D

$\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}$

E

$\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}$

Hence, the following are identities

$\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

The marked are the trigonometric identities

3 0

2 years ago

-4x+3y=-27<br> get y by its self

padilas [110]

3y=4x-27
y=4/3x-9
That’s how you do the equation

3 0

3 years ago

Which is the difference of 21 1/4 - 18 2/4<br> A 2 1/4 B 2 2/4 C 2 3/4 D 3 1/4

PSYCHO15rus [73]

So when you change the mixed numbers into improper fractions, they become 85/4 and 74/4. Your new problem is 85/4-74/4. Basically 85-74. That equals 9. So the improper fraction answer is 9/4. We now make that back into a mixed number, creating 2 1/4, or A.

8 0

3 years ago

Find the absolute value of 35

Wittaler [7]

Answer:

35

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Simplify 2n - 7+3(4n-3)<br> A.14n-16<br> B. -14n+12<br> C.-14n-13<br> D.14n-10

Hoochie [10]

<span>Simplifying 2n + -7 + 3(4n + -3) = 0 Reorder the terms: 2n + -7 + 3(-3 + 4n) = 0 2n + -7 + (-3 * 3 + 4n * 3) = 0 2n + -7 + (-9 + 12n) = 0 Reorder the terms: -7 + -9 + 2n + 12n = 0 Combine like terms: -7 + -9 = -16 -16 + 2n + 12n = 0 Combine like terms: 2n + 12n = 14n -16 + 14n = 0 Solving -16 + 14n = 0 Solving for variable 'n'. Move all terms containing n to the left, all other terms to the right. Add '16' to each side of the equation. -16 + 16 + 14n = 0 + 16 Combine like terms: -16 + 16 = 0 0 + 14n = 0 + 16 14n = 0 + 16 Combine like terms: 0 + 16 = 16 14n = 16 Divide each side by '14'. n = 1.142857143 Simplifying n = 1.142857143</span>

6 0

3 years ago