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larisa86 [58]
2 years ago
7

When r=42, what is the value of 3r-3^3

Mathematics
1 answer:
MrRa [10]2 years ago
8 0
126-27 = 99, hope this helps
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Please help meeee!! Finding a slope of a line
Lelechka [254]

Answer:

\huge\boxed{\sf Slope = \frac{5}{2} }

Step-by-step explanation:

<u>Take any two points or coordinated from the graph.</u>

Let's take (2,2) and (0,-3)

So,

\sf (x_{1},y_{1}) = (2,2)\\\\(x_{2},y_{2}) = (0,-3)

Hence,

\sf Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}  \\\\Slope = \frac{-3-2}{0-2} \\\\Slope = \frac{-5}{-2} \\\\Slope = \frac{5}{2} \\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
8 0
2 years ago
Read 2 more answers
The math test has 15 multiple choice questions, each with 3 answers. If Betty guesses correctly on the first 4 questions,
Sonbull [250]

Answer:

90 percent

Step-by-step explanation:

15 divided by 4 so 3.75 i rounded it and i got 4

8 0
3 years ago
look at the figure shown below which step should be used to prove that point a is equidistant from points c and b
JulijaS [17]
D
is certainly wrong. You could extend the length of AD as far as you want and the two triangles (ABD and ACD) would still be congruent.

C
is wrong as well. The triangles might be similar, but they are more. They are congruent.

B
You don't have to prove that. It is given on the way the diagram is marked.

A
A is your answer. The two triangles are congruent by SAS 
3 0
3 years ago
State whether the lines are parallel, perpendicular or neither. y = x+1 y = -x-2 (5 points) A. Parallel B. Perpendicular C. Neit
Anuta_ua [19.1K]
B. perpendicular is correct
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3 years ago
Use the properties of 30-60-90 and 45-45-90 triangles to solve for x in each of the problems below. Then decode the secret messa
murzikaleks [220]

The trigonometric function gives the ratio of different sides of a right-angle triangle. The given problems can be solved as given below.

<h3>What are Trigonometric functions?</h3>

The trigonometric function gives the ratio of different sides of a right-angle triangle.

\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Tan \theta=\dfrac{Perpendicular}{Base}\\\\\\Cosec \theta=\dfrac{Hypotenuse}{Perpendicular}\\\\\\Sec \theta=\dfrac{Hypotenuse}{Base}\\\\\\Cot \theta=\dfrac{Base}{Perpendicular}\\\\\\

where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.

1st.) x = 5 /Sin(30°)

x = 10

!) sin(45°) = 4/x

x = 4/sin(45°)

x = 4√2

I) Cos(45°) = √3 / x

x = √3 / Cos(45°)

x = √6

E) Tan(60°) = 3√3 / x

x = 3√3 / 3

W) For isosceles right-triangle, the angle made by the legs and the hypotenuse is always 45°.

x = 45°

N) x² + x² = (7√2)²

x = 7

V) Tan(60°) = 7 / x

x = 7√3/3

K) x² + x² = (9)²

x = 9/√2

Y) Sin(60°) = 7√3/x

x = 14

M) Sin(30°) = x/11

x = 11/2

T) Sin(45°) = x/√10

x = √5

A) x + 2x + 90° = 180°

x = 30°

O) Sin(45°) = √2 / x

x = 2

R) Tan(30°) = x / 4

x = 4/√3 = 4√3 / 3

S) Sin(60°) = x / (10/3)

x = 5√3 / 3

Learn more about Trigonometric functions:

brainly.com/question/6904750

#SPJ1

5 0
2 years ago
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