2nd one is the answer to it.
Do 18x18 which equals 324
The answer is: [C]: "Astrologers do not use the scientific method."
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Note: Choice [A] is incorrect. Astrologers do use tools.
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Choice [B] is incorrect. Some astrologers do observe the universe.
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Choice [D] is incorrect. Astrologers may or may not go to college; and whether or not they do or do not is irrelevant as regard to whether to they are considered "scientists".
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Answer:
Step-by-step explanation:
Huhuj
Answer:
77.64% probability that there will be 0 or 1 defects in a sample of 6.
Step-by-step explanation:
For each item, there are only two possible outcomes. Either it is defective, or it is not. The probability of an item being defective is independent of other items. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
The true proportion of defects is 0.15
This means that 
Sample of 6:
This means that 
What is the probability that there will be 0 or 1 defects in a sample of 6?

In which




77.64% probability that there will be 0 or 1 defects in a sample of 6.