2 years ago

Solving equations with zero, one, or infinity

1 answer:

5 0

What do you mean exacly

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Sergeeva-Olga [200]

The answer is sometimes

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Basile [38]

3/(x-2)

The answer is x^2+1+3/(x-2)

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Sever21 [200]

-0.16666666666666666666

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Mazyrski [523]

Answer:

3 to 2

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Vesna [10]

Answer:

B. $x = \sqrt{40}$

Step-by-step explanation:

Using Pythagorean theorem, find the value of x.

Pythagorean theorem is given as $c^2 = a^2 + b^2$

Where,

c is the longest side of a right angled ∆ = the hypotenuse = x

a and b are legs of the right angled ∆ = 2 and 6

Plug in the values into the equation and solve for x

$x^2 = 2^2 + 6^2$

$x^2 = 4 + 36$

$x^2 = 40$

$x = \sqrt{40}$

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3 years ago