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BigorU [14]
3 years ago
12

Solving equations with zero, one, or infinity

Mathematics
1 answer:
labwork [276]3 years ago
5 0
What do you mean exacly
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There are 50 seashells on the beach after one week there are 120 seashells on the beach if this continues the same patterns how
lbvjy [14]

Answer: 330

Step-by-step explanation:first you subtract 50 from 120 = 70 then 70 x the number of days which is 4 = 280 + the seashells at the beginning which is 50 = 330.

4 0
3 years ago
The mapping diagram shows a functional relationship.
Lerok [7]

Answer:

f(4) is 1/2

f(x) = 4 when x is 8

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Item 2
nataly862011 [7]
The expression simplified is 21
27/3 +6*2
(27/3)+(6*2)
(9)+(12)
9+12
21
6 0
3 years ago
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An eagle changes it’s elevation by an average of -14.2 meters every second for 4.8 seconds. What is the change in elevation of t
evablogger [386]

Answer:

Step-by-step explanation:

Let us assume that the eagle's elevation is 100 meters above.

We can multiply -14.2 by 0.8.

We now get -11.36.

We can add this to (-14.2*4).

We now get -11.36 + -56.8.

We can add those together to get the answer.

-11.36 + -56.8 = -68.16.

Then we can add that to 100 (since it is negative).

100 + (-68.16) = 31.84.

The eagle's elevation would be 31.84 meters if its starting position was 100 meters, meaning that the equation would be (a - 68.16).

4 0
3 years ago
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A person is watching a boat from the top of a lighthouse. The boat is approaching the lighthouse directly. When first noticed, t
7nadin3 [17]

To solve this problem, we can use the tan function to find for the distances covered.

tan θ = o / a

Where,

θ = angle = 90° - angle of depression

o = side opposite to the angle = distance of boat from lighthouse

a = side adjacent to the angle = height of lighthouse = 200 ft

When the angle of depression is 16°18', the initial distance from the lighthouse is:

o = 200 tan (90° - 16°18')

o = 683.95 ft

When the angle of depression is 48°51', the final distance from the lighthouse is:

o = 200 tan (90° - 48°51')

o = 174.78 ft

 

Therefore the total distance the boat travelled is:

d = 683.95 ft - 174.78 ft

<span>d = 509.17 ft</span>

4 0
3 years ago
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