Question

The results of a poll show that the percent of people who want a new restaurant is in the interval (62%, 88%)(62%, 88%) . There are 109,482 people in the city.
What is the interval for the number of people who are likely to want this restaurant in their city?

Round to the nearest person.

Enter your answer in the boxes.

Answer 1

Required percentage = (0.62 x 109482, 0.88 x 109,482) = (67879, 96,344)

Answer 2

Answer:

$(67879,96344)$

Step-by-step explanation:

We have been given that the results of a poll show that the percent of people who want a new restaurant is in the interval (62%, 88%). There are 109,482 people in the city.

To find the interval for the number of people who are likely to want this restaurant in their city, we will find 62% and 88% of 109,482.

$62\%\text{ of }109,482=\frac{62}{100}\times 109,482$

$62\%\text{ of }109,482=0.62\times 109,482$

$62\%\text{ of }109,482=67,878.84\approx 67,879$

$88\%\text{ of }109,482=\frac{88}{100}\times 109,482$

$88\%\text{ of }109,482=0.88\times 109,482$

$88\%\text{ of }109,482=96344.16\approx 96344$

Therefore, the interval $(67879,96344)$ represents the number of people who are likely to want this restaurant in their city.