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Keith_Richards [23]
3 years ago
14

I need help on this assignment please!!!

Mathematics
2 answers:
galina1969 [7]3 years ago
7 0
The answer is C. ............
nadya68 [22]3 years ago
3 0
I'm pretty sure the answer is C

Hope I helped!!
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Complete the square for 5x^2 – 30x = 5.
Yuri [45]
First, subtract 5 from both sides, leaving you with 5x^{2} - 30x - 5 = 0
If you use the quadratic formula (a=5), (b=-30), (c=-5)

x=-b +/- √b²-4ac / 2a

x= -(30) +/- √(30)² - 4(5) * (-5) / 2(5)

x= 30 +/- √1000 / 10

x = 3 +/- √10
7 0
3 years ago
The area of a trapezoid is 95 square inches and its height is 10 inches. The length of one base of the trapezoid is 8 inches. Wh
Tanzania [10]

Answer:

C. 11

Step-by-step explanation:

here's my explanation its down below, i wrote it on paper

7 0
2 years ago
Which expression is equivalent? (42x−5y−4z3)−2 A) 256x10y8z6 B) 256 x10y8z6 C) x10y8 256z6 D) y8 256x10z6
Natasha_Volkova [10]
The best answer is c
6 0
3 years ago
If you drive 300 miles and do 70 per hour how much minutes does it take​
dangina [55]

Answer: well I'm sorry I can't help that much but 300÷70(per hour)=4.28571428571 (Yes I did the math in my head) but it would be an estimate of 4 or 5 minutes. If I helped that's the least I can do. Your welcome! Anytime!!

Step-by-step explanation:

5 0
3 years ago
Find an asymptote of this conic section. 9x^2-36x-4y^2+24y-36=0
ki77a [65]
We will begin by grouping the x terms together and the y terms together so we can complete the square and see what we're looking at. (9x^2-36x)-(4y^2+24y)-36=0.  Now we need to move that 36 over by adding to isolate the x and y terms.  (9x^2-36x)-(4y^2+24y)=36.  Now we need to complete the square on the x terms and the y terms.  Can't do that, though, til the leading coefficients on the squared terms are 1's.  Right now they are 9 and 4.  Factor them out: 9(x^2-4x)-4(y^2-6y)=36.  Now let's complete the square on the x's. Our linear term is 4.  Half of 4 is 2, and 2 squared is 4, so add it into the parenthesis.  BUT don't forget about the 9 hanging around out front there that refuses to be forgotten.  It is a multiplier.  So we are really adding in is 9*4 which is 36.  Half the linear term on the y's is 3.  3 squared is 9, but again, what we are really adding in is -4*9 which is -36.  Putting that altogether looks like this thus far: 9(x^2-4x+4)-4(y^2-6y+9)=36+36-36.  The right side simplifies of course to just 36.  Since we have a minus sign between those x and y terms, this is a hyperbola.  The hyperbola has to be set to equal 1.  So we divide by 36.  At the same time we will form the perfect square binomials we created for this very purpose on the left: \frac{(x-2)^2}{4}- \frac{(y-3)^2}{9}=1.  Since the 9 is the bigger of the 2 values there, and it is under the y terms, our hyperbola has a horizontal transverse axis.  a^2=4 so a=2; b^2=9 so b=3.  Our asymptotes have the formula for the slope of m=+/- \frac{b}{a} which for us is a slope of negative and positive 3/2.  Using the slope and the fact that we now know the center of the hyperbola to be (2, 3), we can solve for b and rewrite the equations of the asymptotes.  3= \frac{3}{2}(2)+b give us a b of 0 so that equation is y = 3/2x.  For the negative slope, we have 3=- \frac{3}{2}(2)+b which gives us a b value of 6.  That equation then is y = -3/2x + 6.  And there you go!
8 0
3 years ago
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