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Montano1993 [528]
3 years ago
12

Need help plzzzzz helpppp 20 points and if right I will mark brainlest

Mathematics
1 answer:
shtirl [24]3 years ago
8 0

Answer:

Hi! Okay so i tried to find all the x and y intercepts that matched with (-4,7) and the closest one is C I'm not 100% sure its correct but its the only one that makes the most sense, its coordonated are (-8,4) i'm so sorry if u get it wrong

Step-by-step explanation:

☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆

☆Don't worry i wont ask for brainliest this time☆

Have a nice day!!!!!!!

- Brooklynn Deka

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What is the solution to an equation /
navik [9.2K]

Answer:

Idk what u mean?

Step-by-step explanation:

but i searched it up and here are my results

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true. For equations having one unknown, raised to a single power, two fundamental rules of algebra, including the additive property and the multiplicative property, are used to determine its solutions.Mar 20, 2020

email me if it helps

ty

6 0
3 years ago
What could be the equation for?:
liubo4ka [24]

Answer:

6

Step-by-step explanation:

6

8 0
2 years ago
Which value is in the domain of f(x)?
MatroZZZ [7]

9514 1404 393

Answer:

  4

Step-by-step explanation:

The function definition tells you its domain is ...

  -6 < x ≤ 4

Values -7, -6, and 5 are not in this domain.

Of the listed values, only 4 is in the domain.

7 0
3 years ago
* Let S = Span {(2,-1, 1), (3, 1, 1), (1, 2, 0)}. (i) Calculate the dimension of S.
Sholpan [36]

The span of 3 vectors can have dimension at most 3, so 9 is certainly not correct.

Check whether the 3 vectors are linearly independent. If they are not, then there is some choice of scalars c_1,c_2,c_3 (not all zero) such that

c_1 (2,-1,1) + c_2 (3,1,1) + c_3 (1,2,0) = (0,0,0)

which leads to the system of linear equations,

\begin{cases} 2c_1 + 3c_2 + c_3 = 0 \\ -c_1 + c_2 + 2c_3 = 0 \\ c_1 + c_2 = 0 \end{cases}

From the third equation, we have c_1=-c_2, and substituting this into the second equation gives

-c_1 + c_2 + 2c_3 = 2c_2 + 2c_3 = 0 \implies c_2 + c_3 = 0 \implies c_2 = -c_3

and in turn, c_1=c_3. Substituting these into the first equation gives

2c_1 + 3c_2 + c_3 = 2c_3 - 3c_3 + c_3 = 0 \implies 0=0

which tells us that any value of c_3 will work. If c_3 = t, then c_1=t and c_2 = -t. Therefore the 3 vectors are not linearly independent, so their span cannot have dimension 3.

Repeating the calculations above while taking only 2 of the given vectors at a time, we see that they are pairwise linearly independent, so the span of each pair has dimension 2. This means the span of all 3 vectors taken at once must be 2.

3 0
2 years ago
A table is set for dinner. can the legs of the table and the top of the table lie in parallel planes
Zepler [3.9K]

Answer:

no

Step-by-step explanation:

the legs of a table are perpendicular the top of the table because they intersect at 90° since they are perpendicular, they clearly intersect, so they cannot lie in parallel planes

7 0
3 years ago
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