Answer:
132.8774
Explanation:
amount of salt present iin 3.79l was 132.8774g
Answer:
The answer to your question is V2 = 29.9 ml
Explanation:
Data
Volume 1 = V1 = 35 ml
Pressure 1 = P1 = 1 atm
Temperature 1 = T1 = 150°C
Volume 2 = V2 = ? ml
Pressure 2 = P2 = 2 atm
Temperature 2 = T2 = 450 °C
Process
1.- Convert temperature to °K
Temperature 1 = 150 + 273 = 423°K
Temperature 2 = 450 + 273 = 723°K
2.- Use the Combined gas law to find the volume
P1V1/T1 = P2V2/T2
-Solve for V2
V2 = P1V1T2 / T1P2
-Substitution
V2 = (1 x 35 x 723) / (423 x 2)
-Simplification
V2 = 25305 / 846
-Result
V2 = 29.9 ml
Answer:
For every 4 moles of NO created, 6 moles of H2O are created so the ratio is 4:6
Explanation:
You just need to balance the equation.
NH3 + O2 -> NO + H2O
1. I started with hydrogen; there's 3 on the left and 2 on the right. Multiply them together to find a number they both go into (3×2=6, but in this case 6 hydrogen on each side does not work so I doubled it so there is 12 hydrogen on each side).
This will bring you to this:
4NH3 + O2 -> NO + 6H2O
2. Now get equal amounts of nitrogen on each side. There's 4 nitrogen on the left side, and 1 on the right. Multiply the right by 4. Then you will have this:
4NH3 + O2 -> 4NO + 6H2O
3. Last thing you need to do is have the same amount of oxygen on both sides. On the left you have 2 and on the right you have 10. Get the left to 10 by multiplying it by 5.
Balanced: 4NH3 + 5O2 -> 4NO + 6H2O
In word form, for every reaction between 4 moles of ammonia and 5 moles of oxygen, 4 moles of nitric oxide and 6 moles of water will be created.
I hope this helps!
