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balu736 [363]
3 years ago
9

Identify the compound with the highest magnitude of lattice energy. Identify the compound with the highest magnitude of lattice

energy. CaBr2 CaBr2 MgBr2 SrBr2
Chemistry
1 answer:
Galina-37 [17]3 years ago
4 0

Answer: Option (c) is the correct answer.

Explanation:

According to the Born-Lande equation,

          E = \frac{N_{A}Mz^{+}z^{-}e^{2}}{4 \pi \epsilin_{o} r}

where,   N_{A} = Avogadro's constant

                    r = distance between the anion and cation

                   M = Medlung constant

           z^{+} = charge on the cation

           z^{-} = charge on the anion

                  E = lattice energy

According to this expression, lattice energy is inversely proportional to the distance between the cation and anion. And, when we move down a group then there occurs an increase in the atomic radii of the atoms.

As a result, there will occur a decrease in their lattice energy. Since, the anionic part is same in all the given species but the cationic part is different.

In MgBr_{2} the size of magnesium cation is smaller than calcium, barium and strontium ion. Hence, there will be least distance between Mg and Br ions.

Thus, we can conclude that the magnitude of lattice energy will be the highest in MgBr_{2}.

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A 0.964 gram sample of a mixture of sodium formate and sodium chloride is analyzed by adding sulfuric acid. The equation for the
frosja888 [35]

Answer: 67.8 %.

Explanation:

Okay, let us delve right into the solution to the question;

The balanced chemical reaction is given by the equation (1) below;

2 HCOONa + H2SO4 ---------> 2 CO + 2 H2O + Na2SO4. ----------------------------------------------------------------------------(1).

From the balanced chemical reaction in equation (1) above we can see that; 2 moles of HCOONa reacts with one moles of tetraoxosulphate acid, H2SO4 to produce 2 moles of carbonmonoxide,CO; 2 moles of water, H2O and 1 mole of sodium tetraoxosulphate, Na2SO4.

The parameters given from the question are; total atmospheric pressure, P(t) = 752 torr, volume of CO= 242 mL = 0.242 Litres.

STEP ONE : find the carbon monoxide,CO pressure; P(CO).

Using the formula below;

P(t) = P(CO) + P(H2O). Hence;

P(CO) = P(t) - P(H2O). Note that P(H2O)= 19.8 torr.

==>P(CO)= 752 torr - 19.8 torr = 732.2 torr.

STEP TWO: calculate the number of moles of Carbonmonoxide,CO.

Using the formula below;

Number of moles= pressure(P) × volume(v) / gas constant(R) × temperature (T).

That is, n= PV/RT.

n= 732 torr × 0.242 Litres/ 62.4 × 295.15.

= 9.62 × 10^-3 mol of CO.

STEP THREE:

2 moles of HCOONa = 2 moles of CO.

=> 2 moles of HCOONa = 2 moles of CO/ 2 moles of CO = 1 mol( HCOONa/ CO).

Then, 9.62 × 10^-3 mol of CO × 1 mol( HCOONa/ CO).

==> 9.62 × 10^-3 mol HCOONa × molar masss of HCOONa(68 grams/mol)

= 0.654 grams.

Therefore, the percentage of sodium formate in the original mixture = 0.654 grams/ 0.964 gram × 100 = 67.8 %.

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How does changing the amount of one substance affect a mixtures identity and a compounds identity iscience?
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Explanation:

A compound is defined as follows.

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  • The atoms bonded in a compound are in specific proportion.
  • A compound is formed by chemical combination.
  • For a compound, melting point and boiling point is defined.

A mixture is defined as follows.

  • Mixtures are impure substance.
  • The bonded atoms in a mixture are in any proportion.
  • A mixture is formed by physical combination.
  • For a mixture, melting point and boiling point is not defined.

On changing the amount of one substance will affect the formation of compound as a compound requires atoms to be bonded in a specific proportion. Whereas changing the amount of one substance will not affect the formation of mixtures  as atoms can be bonded in any proportion in a mixture.

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