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LUCKY_DIMON [66]
3 years ago
13

Why can’t we see black holes? Question 11 options: A.Because they don't want to be seen. B.Because the sun is too far away from

them. C.Because they are supermassive. D.Because no light can get out.
Physics
1 answer:
Vika [28.1K]3 years ago
6 0

We can't see black holes because D) no light can get out

Explanation:

Black holes are the result of the gravitational collapse of a supermassive star.

The life of a supermassive star ends with a huge explosion, called supernova, that leaves behing a super-dense core called black hole.

Black holes are the most dense objects of the universe, having a huge mass in a super small size. For this reason, the gravitational force exerted by a black hole in its proximity is so strong that even light is not able to escape from the gravitational field. For this reason, light from a black hole is not able to reach us, and so we are not able to see these objects.

The "edge" of space beyond which light remains "trapped" inside the black hole is called event horizon, and no object can escape this region of space.

The radius of the event horizon of a black hole is called Schwarzschild radius and it is given by:

r=\frac{2GM}{c^2}

where

G is the gravitational constant

M is the mass of the black hole

c is the speed of light

Learn more about space:

brainly.com/question/2887352

brainly.com/question/10934170

#LearnwithBrainly

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Two charged concentric spherical shells have radii of 11.0 cm and 14.0 cm. The charge on the inner shell is 3.50 ✕ 10−8 C and th
Sergio039 [100]

Answer:

The magnitude of the electric field are 2.38\times10^{4}\ N/C and 1.09\times10^{4}\ N/C

Explanation:

Given that,

Radius of inner shell = 11.0 cm

Radius of outer shell = 14.0 cm

Charge on inner shell q_{inn}=3.50\times10^{-8}\ C

Charge on outer shell q_{out}=1.60\times10^{-8}\ C

Suppose, at r = 11.5 cm and at r = 20.5 cm

We need to calculate the magnitude of the electric field at r = 11.5 cm

Using formula of electric field

E=\dfrac{kq}{r^2}

Where, q = charge

k = constant

r = distance

Put the value into the formula

E=\dfrac{9\times10^{9}\times3.50\times10^{-8}}{(11.5\times10^{-2})^2}

E=2.38\times10^{4}\ N/C

The total charge enclosed  by a radial distance 20.5 cm

The total charge is

q=q_{inn}+q_{out}

Put the value into the formula

q=3.50\times10^{-8}+1.60\times10^{-8}

q=5.1\times10^{-8}\ C

We need to calculate the magnitude of the electric field at r = 20.5 cm

Using formula of electric field

E=\dfrac{kq}{r^2}

Put the value into the formula

E=\dfrac{9\times10^{9}\times5.1\times10^{-8}}{(20.5\times10^{-2})^2}

E=1.09\times10^{4}\ N/C

Hence, The magnitude of the electric field are 2.38\times10^{4}\ N/C and 1.09\times10^{4}\ N/C

7 0
3 years ago
25000 seconds is how many days?
KatRina [158]

0.289352 days is the 25000 seconds.

6 0
3 years ago
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A turntable with a moment of inertia of 7.2 × − ⋅ rotates freely with an angular speed of 6.5 ⁄ . Riding on the rim of the turnt
irina1246 [14]

Answer:

turntable with a moment of inertia of 7.2 × − ⋅ rotates freely with an angular speed of 6.5 ⁄ . Riding on the rim of the turntable, 2 from the center, is a hamster. When the hamster walks to the center of the turntable, the angular speed of the turntable becomes ⁄. What is the mass of hamster?

Explanation:

6 0
2 years ago
Determine the magnitude of the resultant force acting on a 1.5 −kg particle at the instant t=2 s, if the particle is moving alon
Phoenix [80]

Answer:

F = 63N

Explanation:

M= 1.5kg , t= 2s, r = (2t + 10)m and

Θ = (1.5t² - 6t).

magnitude of the resultant force acting on 1.5kg = ?

Force acting on the mass =

∑Fr =MAr

Fr = m(∇r² - rθ²) ..........equation (i)

∑Fθ = MAθ = M(d²θ/dr + 2dθ/dr) ......... equation (ii)

The horizontal path is defined as

r = (2t + 10)

dr/dt = 2, d²r/dt² = 0

Angle Θ is defined by

θ = (1.5t² - 6t)

dθ/dt = 3t, d²θ/dt² = 3

at t = 2

r = (2t + 10) = (2*(2) +10) = 14

but dr/dt = 2m/s and d²r/dt² = 0m/s

θ = (1.5(2)² - 6(2) ) = -6rads

dθ/dt =3(2) - 6 = 0rads

d²θ/dt = 3rad/s²

substituting equation i into equation ii,

Fr = M(d²r/dt² + rdθ/dt) = 1.5 (0-0)

∑F = m[rd²θ/dt² + 2dr/dt * dθ/dt]

∑F = 1.5(14*3+0) = 63N

F = √(Fr² +FΘ²) = √(0² + 63²) = 63N

7 0
3 years ago
How is fission used to produce electricity? a. the heat generated from the fission reaction is used to boil water, which rises a
denis-greek [22]

According to the research, the correct option is a. The heat generated from the fission reaction is used to boil water, which rises and spins a turbine.

<h3>How is fision used to produce electricity?</h3>

In fusion, two atoms come together to form a larger one, releasing enormous amounts of energy in the process, this is used by generators to produce electricity.

As a result of nuclear fusion, large amounts of heat are generated that are used to produce pressurized steam, which allows mechanical energy to be obtained to start up electric power generators.

Therefore, we can conclude that according to the research, the correct option is a. The heat generated from the fission reaction is used to boil water, which rises and spins a turbine.

Learn more about fision reaction here: brainly.com/question/13207914

#SPJ1

4 0
2 years ago
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