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3 years ago

What is empirical evidence and what is it not

1 answer:

7 0

Empirical evidence refers to a scientific information that are obtained as a result of observation. The observation may occur through experience or through experimentation. Gathering empirical data is very important in science because all experiments must be empirically based.

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A 5 kg block moves in a straight line on a horizontal frictionless surface under the influence of a force that varies with posit

jekas [21]

The work done is 315 J

Explanation:

The graph is missing: find it in attachment.

The work done by a variable force is given by

$W=\int F(x) dx$

where

F(x) is the magnitude of the force

x is the position

On a force vs position graph, the work done is equivalent to the area under the graph. Therefore, in order to find the work done as the block moves from x = 0 to x = 8.0 m, we have to calculate the area under the graph between these two points.

Each square corresponds (vertically) to 45 N, so the area of the first trapezium between x = 0 and x = 4.0 m is

$A_1 = \frac{(4+2)\cdot 2\cdot 45)}{2}=270$

Then we have to find the area of the triangle between x = 6.0 m and x = 8.0 m:

$A_2 = \frac{1}{2}(2)(45)=45$

Therefore, the total area (and the work done) is

$W=A_1+A_2=270+45=315 J$

Learn more about work:

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5 0

3 years ago

89 POINTS IF YOU ANSWER

Evgen [1.6K]

I'm pretty sure it's Protons

8 0

3 years ago

Read 2 more answers

HELP ME ASAP PLEASE!!!!!

solmaris [256]

Answer:

f λ = c = 3.00E8 frequency * wavelength = speed of light

λ = c / f = 3.00E8 / 4.0E14 = 7.5E-7 m

Note 1 angstrom = 1.00E-10 m and 1 milli-micron = 1.00E-9 m

So the wavelength would be 7500 angstroms

The visible spectrum is 4000 A - 7000 A or 400 - 700 milli-microns

3 0

2 years ago

Solve a hollow steel shaft has an outside diameter of 100mm and inside diameter of 75 mm.the shaft is subjected to a pure torque

FrozenT [24]

The maximum shearing stress in hollow shaft is 66.125 MPa.
The magnitude of angle of twist is 0.0279 rad.
The power generated by the shaft is 157 kW.

<h3>What is power ?</h3>

Power in a rotating body like shaft is the product of Torque and the angular speed of that shaft.

P = Tω

The Torque is related to the shearing stress is

T = π/16 xτ(Do³ -Di³)

* Given is the Torque T= 7.5 kN.m, the inner diameter Di = 0.075m, outer diameter Do= 0.1m

Then, the maximum shearing stress will be

7.5 x 10³ = π/16 xτ x (0.1³ - 0.075³)

τ = 66.125 MPa

Thus, the shearing stress is 66.125 MPa.

* From the Torque equation

T/J = Gθ/l

Where, J = π/32 (Do⁴ -Di⁴) = 0.00000671 m⁴

l = length of shaft = 2m, modulus of rigidity G = 80GPa = 80x 10⁹ Pa.

Substitute the values, we get the angle of twist

7.5 x10³ /0.00000671 = 80x 10⁹xθ/2

θ = 0.0279 rad.

Thus, the angle of twist is0.0279 rad.

* Power generated by the shaft is

P = 2πNT/60

where N = revolution/ minute = 200

Put the values, we get

P = 2π x 200 x 7500/60

P = 157 kW.

Thus, the power generated is 157 kW.

Learn more about power.

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5 0

2 years ago

What is the wavelength in nm of a light whose first order bright band forms a

scoundrel [369]

The wavelength of the first order bright band light light is 714 nm .

Explanation:

We have to find the wavelength of the first order brightness of a light. Here we are using Huygen's principle of light.

The formula is

nλ =d sinθ

where, n is the order of maximum

λ is the wavelength of light

d is the distance between the lines on diffraction grating.

θ is the angle.

For the given equation n is 1 because the problem states that the light forms 1st order bright band

λ is unknown.

d = $\frac{1}{700,000}$ or 0.0000014 m

sin (30) = 0.5

so,

1(λ) = (0.0000014)(0.5)

= 0.0000000714

= 714 nm

Thus, The wavelength of the first order bright band light light is 714 nm .

3 0

3 years ago