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Damm [24]
3 years ago
9

Argon, neon, and xenon are examples of

Physics
1 answer:
Luda [366]3 years ago
3 0
1. your in highschool you should know this but its A
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Recall that if a line is parallel to the vector v and passes through the point P0, which is the tip of the position vector r0, t
Elenna [48]

Answer:

The vector equation of the line is

                                \overrightarrow{r}=+t

Parametric equations for given line are

                                       x=7+t\\y=-8+6t\\z=3-13t

Explanation:

The vector equation of the line is given by

                                     r(t) = r_{o} + tv

r₀ = (7, -8, 3)

v = (1, 6, -13)

At these points the vector equation for this line is:

\overrightarrow{r}=\overrightarrow{r_{o}}+t\overrightarrow{v}\\\overrightarrow{r}=+t

Parametric equations for given line are

                                       x=7+t\\y=-8+6t\\z=3-13t

8 0
3 years ago
Which force can affect an object without direct physical contact?
denis-greek [22]
Gravity affet everything and it touches nothing.
Hope this helps!
8 0
3 years ago
Read 2 more answers
Two point charges of equal magnitude are 8.0 cm apart. At the midpoint of the line connecting them, their combined electric fiel
bagirrra123 [75]

Answer:

r = 8/2 = 4cm = 0.04m

k = 9×10^9

Enet = 51 N/C

Enet = E1 + E2

since E1 = E2

E1 = Enet/2 = 51/2

E/2 = kq/r²

q = Er²/2k

q = (51 × 0.04²)/(2×9×10^9)

q = 4.5×10^-12 C

q1 = q2 = 4.5 pC

Explanation:

The electric field is a region around a

charge in which it exerts electrostatic force

on another charges. While the strength of

electric field at any point in space is called

electric field intensity. It is a vector

quantity. Its unit is NC¯¹.

According to coulomb’s law ,if a unit

positive charge q (call it a test charge) is

brought near a charge q (call a field

charge) placed in space,the charge q will

experience a force. The value of this force

depends upon the distance between the

two charges. If the charge q is moved

away from q ,this force would decrease till

at a certain distance the force would be

practically reduced to zero. The charge q

is then out of the influence of charge q.

The region of space surrounding the charge

q in which it exerts a force on the charge

q is known as E.F of the charge

q. Mathematically it is expressed as:

E =F/q

The direction of the vector E is the same

as the direction of F,because q is a

positive scalar. Dimensionally,the E.F is

force per unit charge,and its SI unit is the

newton/coulomb (N/C).

7 0
2 years ago
In a circuit a battery is used to
Anarel [89]

Produce power through the circuit.

7 0
3 years ago
Read 2 more answers
. A car with a mass of 700-kg changes its speed from 10.0 m/s to 30.0 m/s in a displacement of 50.0 meters. Calculate the net fo
Nezavi [6.7K]

Answer:

5600N

Explanation:

Given parameters:

Mass of car  = 700kg

Initial velocity  = 10m/s

Final velocity  = 30m/s

Displacement  = 50m

Unknown:

Net force acting on the car  = ?

Solution:

To find the force acting on a body, it is pertinent we know the mass and acceleration.

 Force  = mass x acceleration

Now;

 Let us find the acceleration from the kinematics equations:

 v²  = u²  + 2aS

 v is the final velocity

 u is the initial velocity

 a is the acceleration

 S is the distance

  30²  = 10²  + (2 x a x 50)

 900 = 100 + 100a

      100a  = 800

           a  = 8m/s²

Therefore;

     Force  = 700 x 8  = 5600N

6 0
3 years ago
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