Question

1. A student in lab measures 4.6 grams of copper for an experiment. Upon further analysis he determines that he should have measured out 4.7 grams of copper. What is his percent error?

Answer 1

Answer:

$2.13\%$

Explanation:

Quantity of copper measured by a student = 4.6 grams

Original quantity of copper = 4.7 grams

Error in measurement = Original quantity of copper - Quantity of copper measured by a student  $=4.7-4.6=0.1$ grams

To find the percent error, apply the following formula:

Percent error = (Error in measurement / Original quantity of copper) × 100

$=\frac{0.1}{4.7}(100)=2.13\%$