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VashaNatasha [74]
2 years ago
7

PLEASE HELP PLEASE HELP PLEASE HELP

Chemistry
1 answer:
Katen [24]2 years ago
5 0

Answer: To increase the flow of fluid in our everyday lives, you need to get some exercise.

Explanation: You're welcome and can you pls give me the brainiest

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Identify the hybridization of the n atom in nf3.
alexgriva [62]
The hybridization would be sp2. it goes from s, sp, sp2, sp3, sp3d, and so on. each bond gets one more level. since there are three bonds connecting to nitrogen it would be sp2.
7 0
3 years ago
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In the cathode ray tube experiment, J. J. Thomson passed an electric current through different gases inside a cathode ray tube i
Ber [7]

It showed that atoms can be divided into smaller parts.

It showed that all atoms contain electrons.

Explanation:

The experiment carried out by J.J Thomson on the gas discharge tube by passing electric current through a tube filled with many different gases provided a good insight into the structure of an atom.

This experiment led to the development of the plum pudding model of the atom.

  • Cathode rays and it properties were discovered in this set up.
  • It furnished the scientific community with evidences that atoms can be divided into smaller parts.
  • Since atoms now contain some subatomic particles, they can be broken down in like manner into further bits.
  • The cathode rays which were later termed electrons became a fundamental particles known for every atom.

learn more:

Rutherford's model of the atom brainly.com/question/1859083

#learnwithBrainly

6 0
3 years ago
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the standard change in Gibbs free energy is Δ????°′=7.53 kJ/molΔG°′=7.53 kJ/mol . Calculate Δ????ΔG for this reaction at 298 K29
Vera_Pavlovna [14]

Answer:

ΔG = 16.218 KJ/mol

Explanation:

  • dihydroxyacetone phosphate ↔ glyceraldehyde-3-phosphate
  • ΔG = ΔG° - RT Ln Q

∴ ΔG° = 7.53 KJ/mol * ( 1000 J / KJ ) = 7530 J/mol

∴  R = 8.314 J/K.mol

∴ T = 298 K

∴ Q = [glyceraldehyde-3-phosphate] / [dihydroxyacetone phosphate]

⇒ Q = 0.00300 / 0.100 = 0.03

⇒ ΔG = 7530J/mol - (( 8.314 J/K.mol) * ( 298 K ) * Ln ( 0.03 ))

⇒ ΔG = 16217.7496 J/mol ( 16.218 KJ/mol )

5 0
3 years ago
How many molecules are in 41.8 g of sulfuric acid
Anton [14]

Answer

× 10²³ molecules are in 41.8 g of sulfuric acid

Explanation

The first step is to convert 41.8 g of sulfuric acid to moles by dividing the mass of sulfuric acid by its molar mass.

Molar mass of sulfuric acid, H₂SO₄ = 98.079 g/mol

Mole=\frac{Mass}{Molar\text{ }mass}=\frac{41.8\text{ }g}{98.079\text{ }g\text{/}mol}=0.426187053\text{ }mol

Finally, convert the moles of sulfuric acid to molecules using Avogadro's number.

Conversion factor: 1 mole of any substance = 6.022 × 10²³ molecules.

Therefore, 0.426187053 moles of sulfuric acid is equal

\frac{0.426187053\text{ }mol}{1\text{ }mol}\times6.022×10²³\text{ }molecules=2.57\times10^{23}\text{ }molecules

Thus, 2.57 × 10²³ molecules are in 41.8 g of sulfuric acid.

3 0
1 year ago
Which force is most responsible for binding together an atom’s protons and neutrons?
vampirchik [111]

Answer:

Hello There!!

Explanation:

I believe the answer is nuclear.

hope this helps,have a great day!!

~Pinky~

3 0
2 years ago
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