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3 years ago

PLEASE HELP PLEASE HELP PLEASE HELP

Chemistry

1 answer:

Katen [24]3 years ago

5 0

Answer: To increase the flow of fluid in our everyday lives, you need to get some exercise.

Explanation: You're welcome and can you pls give me the brainiest

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Write E in the blank if the material is heterogeneous or O if it is homogeneous.

Advocard [28]

Answer/Explanation:

Wood: E

Freshly brewed black coffee: O

Water: O

Lucky Charms: E

Salt: O

Dirt: E

Sausage and mushroom pizza: E

Air: O

Milk: O

Gold: O

Any mixture that looks the same through the substance is homogenous. The different parts are unable to be visibly seen. (Any periodic element is homogenous)

Any mixture that can be easily determined a mix and cannot be evenly separated or dispersed is heterogenous.

8 0

3 years ago

Assume a hydrogen atom has an electron in the n-level corresponding to the month of your birthday (jan = 1, feb = 2, etc.) calcu

luda_lava [24]

My Birthday is in April, So, electron of H atom is in n=4( pfund series).

Ionisation Energy= +13.6(z^2/n^2)
= +13.6(1/16)
= +0.85 eV

6 0

3 years ago

Read 2 more answers

A sample of seawater weighs 250 g and has a volume of 173 ml. What is the density of seawater?

kari74 [83]

Answer:

<h2>The answer is 1.45 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass of seawater = 250 g

volume = 173 mL

It's density is

$density = \frac{250}{173} \\ = 1.4450867052...$

We have the final answer as

Hope this helps you

8 0

3 years ago

A sample of gas with an initial volume of 12.5 L at a pressure of 784 torr and a temperature of 295 K is compressed to a volume

Kipish [7]

Answer:

Final pressure in (atm) (P1) = 6.642 atm

Explanation:

Given:

Initial volume of gas (V) = 12.5 L

Pressure (P) = 784 torr

Temperature (T) = 295 K

Final volume (V1) = 2.04 L

Final temperature (T1) = 310 K

Find:

Final pressure in (atm) (P1) = ?

Computation:

According to combine gas law method:

$\frac{PV}{T} =\frac{P1V1}{T1} \\\\\frac{(784)(12.5)}{295} =\frac{(P1)(2.04)}{310}\\\\33.22 = \frac{(P1)(2.04)}{310}\\\\P1=5,048.18877$

⇒ Final pressure (P1) = 5,048.18877 torr

⇒ Final pressure in (atm) (P1) = 5,048.18877 torr / 760

⇒ Final pressure in (atm) (P1) = 6.642 atm

3 0

4 years ago

Describe how to prepare 10 ml of 5, 10, 15, and 20 micro M CV solution using a 25 microM CV stock solution

zalisa [80]

A calibration curve requires the preparation of a set of known concentrations of CV, which are usually prepared by dieting a stock solution whose concentration is known.

4 0

3 years ago