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miv72 [106K]
3 years ago
12

if the distance between the two objects is tripled how does this affect the overall strength of the electric force between them

Physics
1 answer:
worty [1.4K]3 years ago
8 0
Taking into account the Coulomb's Law: F_e = K\cdot \frac{Q_1\cdot Q_2}{d^2}

If the value of "d" is tripled:

<span>F_e = K\cdot \frac{2Q_1\cdot Q_2}{(3d)^2} = K\cdot \frac{Q_1\cdot Q_2}{9d^2} =\bf \frac{F_e}{9}

The new force is nine times smaller.</span>
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