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3 years ago

12

if the distance between the two objects is tripled how does this affect the overall strength of the electric force between them

1 answer:

worty [1.4K]3 years ago

8 0

Taking into account the Coulomb's Law: $F_e = K\cdot \frac{Q_1\cdot Q_2}{d^2}$

If the value of "d" is tripled:

<span> $F_e = K\cdot \frac{2Q_1\cdot Q_2}{(3d)^2} = K\cdot \frac{Q_1\cdot Q_2}{9d^2} =\bf \frac{F_e}{9}$

The new force is nine times smaller.</span>

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3 years ago

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3 years ago

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2 years ago

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victus00 [196]

Answer:

a) $t=195.948N.m$

b) $\phi=13.6 \textdegree$

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a)

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b)

Generally the equation for torque due to weight is mathematically given by

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3 years ago