2. A girl whose mass is 55kg stands on a spring weighing machine inside a lift. When the lift starts to ascend, its acceleration

A tub of water is placed in a small room and heat is removed from the room. What will most likely occur if enough heat is remove

NARA [144]

Answer:

(A)The water will freeze.

Explanation:

Heat is the energy that when transferred causes change in temperature. If heat is added to a body by some process the bodies temperature increases and if heat is removed from a body by some process the temperature reduces.

In this case if enough heat is removed from the room the internal movement of the water particles will slow down causing the water to form crystal lattice thus forming ice. So, the water will freeze.

6 0

2 years ago

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Energy stored between charged particles is called

olga nikolaevna [1]

Electrical potential energy is the energy stored between charged particles.

7 0

2 years ago

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Two charges that are separated by one meter exert 1-n forces on each other. if the magnitude of each charge is doubled, the forc

Goshia [24]

The electrostatic force between the two charges is
$F=k_E \frac{q_1 q_2}{r^2}$
where q1 and q2 are the magnitudes of the two charges, and r the distance between them.

We can see from the formula that F is proportional to the product between the two charges:
$F \sim q_1 q_2$
so, if the magnitude of each charge is doubled, the new force will get a factor 4:
$F' \sim (2 q_1 )(2 q_2 )=4 q_1 q_2 =4 F$
So, the new force will be 4 times the original force:
$F' = 4 \cdot 1N= 4N$

5 0

2 years ago

A charge of 6.7 × 10^-15 coulombs is located at a point where its potential energy is 5.6 × 10^-12 joules. What is the electric

natita [175]

Answer:

C. 8.4 × 10^2 volts

Explanation:

The potential energy of a charge is given by:

$U=qV$

where

q is the magnitude of the charge

V is the electric potential

In this problem, we have

$q=6.7\cdot 10^{-15} C$ is the charge

$U=5.6\cdot 10^{-12} J$ is the potential energy

Re-arranging the formula and using these numbers, we can find the electric potential:

$V=\frac{U}{q}=\frac{5.6\cdot 10^{-12} J}{6.7\cdot 10^{-15} C}=835.8 V = 8.4\cdot 10^2 V$

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2 years ago

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A beaker contains 450g of water at a temperature of 24C, The therman capacity of the beaker is negligible and no heat is gained

valentina_108 [34]

Given:

450 grams of water (Tw = 24 C)
Thermal capacity of the beaker = negligible
Q = 0
Tice = 0 C
Tfinal = 8 C

450g * (Tf - Tw) + m_ice * (Tice - Tw) = 0

450g * (8 - 24) + m_ice (0 - 24) = 0

solve for m_ice

8 0

2 years ago