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Sedbober [7]
2 years ago
7

How does an inclined plane work? A A small input force is exerted over a long distance. B A large output force is exerted over a

long distance. C The input force is exerted in the direction opposite to the output force. D The input force is in the direction of the output force, but is larger.
Physics
1 answer:
zavuch27 [327]2 years ago
6 0
An inclined plane, just like all simple machines, makes work easier. I think it is a type of simple machines. Therefore, I think the best answer is A.
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A 42.0-cm diameter disk rotates with a constant angular acceleration of 2.70 rad/s2. It starts from rest at t = 0, and a line dr
Zielflug [23.3K]

Answer:

6.21 rad/s

1.3041 m/s, 0.567 m/s²

106.4778\ ^{\circ}

Explanation:

\omega_f = Final angular velocity

\omega_i = Initial angular velocity = 0

\alpha = Angular acceleration = 2.3 rad/s²

\theta = Angle of rotation

t = Time taken = 2.3 s

Equation of rotational motion

\omega_f=\omega_i+\alpha t\\\Rightarrow \omega_f=0+2.7\times 2.3\\\Rightarrow \omega_f=6.21\ rad/s

The angular speed is 6.21 rad/s

Linear velocity is given by

v=r\omega\\\Rightarrow v=0.21\times 6.21\\\Rightarrow v=1.3041\ m/s

Linear velocity is 1.3041 m/s

Tangential acceleration is given by

a_t=r\alpha\\\Rightarrow a_t=0.21\times 2.7\\\Rightarrow a_t=0.567\ m/s^2

Tangential acceleration is 0.567 m/s²

\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \theta=0\times t+\dfrac{1}{2}\times 2.7\times 2.3^2\\\Rightarrow \theta=7.1415\ rad

In degress the angle would be

57.3+7.1415\times \dfrac{180}{\pi}=466.47780\ ^{\circ}

From x axis it would be

466.47780-360=106.4778\ ^{\circ}

The angle is 106.4778\ ^{\circ} from x axis

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3 years ago
A roller coaster starts from rest at point a and continues to point b on a frictionless track. what best describes the changes i
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157-1.3=155.7psi

At 2%:

0.16×64 = 10.24

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