Tan 2x - cot x = 0
2tan x / (1 - tan^2 x) - 1/tan x = 0
2tan^2 x - (1 - tan^2 x) = 0
2tan^2 x - 1 + tan^2 x = 0
3tan^2 x - 1 = 0
tan^2 x = 1/3
tan x = + or - 1/√3
Answer: x=0,\root(3)(3)
Step-by-step explanation: Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
Brainliest or a thank you please? :))
Corresponding angles- a, d, h, l and s
Alternate interior- c, f, i, o, and t
Same side interior- e, g, k, m, and p
Alternate exterior- n, q, r
• for j and b I’m not sure
Answer:
its about checkers cou nt and answer
Step-by-step explanation:
Combine like terms
-6x^2+2y + -1 +2x^2 + -5y +3
( -6x^2+2x^2)+(2y-5y)+(-1+3)
= -4x^2+3y+2
Answer : C
I hope that's help !
