Ask question

Ask question

All categories

3 years ago

8

Which choice shows three lengths that cannot be the lengths of the three sides of a triangle

1 answer:

Semmy [17]3 years ago

3 0

For triangles Sum of any Two sides should be always more than the length of the Third side.
A) 2cm,8cm,8cm
8+8=16 >2 True
8+2=10 >8, True
8+2=10 >8, True
B) 2cm,3cm,6cm
2+3=5 > 6 False. It is impossible in a triangle.
3+6=9 > 2 True
2+6=8 >3 True

The answer is B.

You might be interested in

BRAINLIEST + Points! Help in need and please explain!

Elanso [62]

C., because 60 is half of 120, and 12% is half of 24%

hope it is right

4 0

3 years ago

Read 2 more answers

It cost Jocelyn $5.60 to send 56 text messages. How much would it cost to send 198

victus00 [196]

Answer:

$19.8

Step-by-step explanation:

To find the answer, find the ratio.

7 0

3 years ago

Read 2 more answers

Can you divide by zero

ANTONII [103]

Answer:

No

Step-by-step explanation:

When you divide by 0, you will get an undefined error. When you try to graph a divide by 0, you will get asymptotes.

3 0

3 years ago

Read 2 more answers

Mr wells drew a plan for a rectangle dog run three of the vertices are (2 1/3, 7 1/2), (12, 7 1/2), and (12, 1) what are the coo

melisa1 [442]

Answer:

Step-by-step explanation:

let 4th fourth vertex be D (x,y)

A(2 1/3,7 1/2),B(12, 7 1/2),C(12,1)

or A(7/3,15/2),B(12,15/2),C(12,1)

Mid-point of diagonal AC is P((7/3+12)/2,(15/2+1))

Mid -point of diagonal BD is P((12+x)/2,(15/2+y)/2)

(Because mid -point of diagonal is same.)

(12+x)/2=(7/3+12)/2

12+x=7/3+12

x=7/3

(15/2+1)/2=(15/2+y)/2

15/2+1=15/2+y

y=1

so fourth vertex is (7/3,1)

8 0

3 years ago

Don and Marie like to go to a good restaurant. Dinners are $16 to $19 dollars with soup or salad. A beverage is $1.50. Dessert i

Vanyuwa [196]

40.25 you add everything together then multiply by .6

8 0

3 years ago

Read 2 more answers