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aniked [119]
3 years ago
10

The process to separate the various components of a liquid mixture is called a fractional distillation true false

Chemistry
2 answers:
balandron [24]3 years ago
5 0

The answer is true. I just had this question on a test and I got it wrong for saying false.

Black_prince [1.1K]3 years ago
4 0
Decantation<span>Decantation is a process for the separation of mixtures, by removing a layer of liquid, generally one from which a precipitate has settled. The purpose may be either to produce a clean decant, or to remove undesired liquid from the precipitate (or other layers). Separate liquids
so it is false</span>
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Using the periodic table, choose the more reactive nonmetal.<br> Te or O
jolli1 [7]

the answer is Te because O is oxygen.

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What is the best definition of solar radiation?(Giving brainliest)
topjm [15]

Answer:

energy from the sun that reaches earth

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Acetone is one of the most important solvents in organic chemistry. It is used to dissolve everything from fats and waxes to air
Phantasy [73]

Answer:

The half-life time, the team equired for a quantity to reduce to half of its initial value, is 79.67 seconds.

Explanation:

The half-life time = the time required for a quantity to reduce to half of its initial value. Half of it's value = 50%.

To calculate the half-life time we use the following equation:

[At]=[Ai]*e^(-kt)

with [At] = Concentration at time t

with [Ai] = initial concentration

with k = rate constant

with t = time

We want to know the half-life  time = the time needed to have 50% of it's initial value

50 = 100 *e^(-8.7 *10^-3 s^- * t)

50/100 = e^(-8.7 *10^-3 s^-1 * t)

ln (0.5) = 8.7 *10^-3 s^-1 *t

t= ln (0.5) / -8.7 *10^-3  = 79.67 seconds

The half-life time, the team equired for a quantity to reduce to half of its initial value, is 79.67 seconds.

4 0
3 years ago
Which of the following statements best explains why Native Americans were overtaken so easily by European settlers?
MaRussiya [10]

Answer:

I don't see any following statements

Explanation:

could you give me some and I'll be happy to help : )

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3 years ago
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An unknown triprotic acid (H3A) is titrated with NaOH. After the titration Ka1 is determined to be 0.0013 and Ka2 is determined
e-lub [12.9K]

Answer:

6.68 X 10^-11

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From the second Ka, you can calculate pKa = -log (Ka2) = 6.187

The pH at the second equivalence point (8.181) will be the average of pKa2  and pKa3. So,

8.181 = (6.187 + pKa3) / 2

Solving gives pKa3 = 10.175, and Ka3 = 10^-pKa3 = 6.68 X 10^-11

7 0
3 years ago
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