1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
amid [387]
4 years ago
14

Given the ionic formula below, what is the charge on ion X? Be sure to

Chemistry
1 answer:
Leviafan [203]4 years ago
4 0

Answer:

Charge on X  = (+ 2)

Explanation:

Charge on one Cl = -1

So Charge on two Cl = -2

The molecule = Neutral = 0 charge

So, to make total charge = 0 , the X should have +2 charge

XCl2 = +2 -2 = 0

X = +2

Alkaline earth metals(Be , Mg , Ca , Sr) form such type of compounds.

Example :

MgCl_{2}

CaCl_{2}

You might be interested in
The human body is about 9.5% carbon atoms, with a small fraction of that carbon being radioactive carbon-14. Carbon dating is a
maw [93]

Answer:The age can be determined by utilizing carbon-14, a radioactive isotope of carbon.

Explanation:

8 0
3 years ago
Complete the following table of neutralization reaction and also write down the names of acid base and salt in it.​
scZoUnD [109]

Answer:

K

SO4

Br

Explanation:

HNO3+K

SO4+NH4OH

Br+KOH

5 0
3 years ago
During the chemical reaction given below 21.71 grams of each reagent were allowed to react. Determine how many grams of the exce
swat32

Answer: 16.32 g of O_2 as excess reagent are left.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} SO_2=\frac{21.71g}{64g/mol}=0.34mol

\text{Moles of} O_2=\frac{21.71g}{32g/mol}=0.68mol

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)  

According to stoichiometry :

2 moles of SO_2 require = 1 mole of O_2

Thus 0.34 moles of SO_2 will require=\frac{1}{2}\times 0.34=0.17moles  of O_2

Thus SO_2 is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

Moles of O_2 left = (0.68-0.17) mol = 0.51 mol

Mass of O_2=moles\times {\text {Molar mass}}=0.51moles\times 32g/mol=16.32g

Thus 16.32 g of O_2 as excess reagent are left.

3 0
3 years ago
Naphthalene combustion may be used to calibrate the heat capacity of a bomb calorimeter. The heat of combustion of naphthalene i
tino4ka555 [31]

Answer:

.

Explanation:

5 0
3 years ago
What is the formula for the polyatomic ion and name the following compound<br>Sn(NO2)2​
garri49 [273]
There are 9 polyatomic ions so which one and the compound “Sn(NO2)2 is Tin(ll) Nitrite
3 0
3 years ago
Read 2 more answers
Other questions:
  • According to the nebular theory what are asteroids and comets
    14·1 answer
  • You have seven closed containers, each with equal masses of chlorine gas (cl2). you add 10.0 g of sodium to the first sample, 20
    6·1 answer
  • If the aluminum block is initially at 25 ∘C, what is the final temperature of the block after the evaporation of the alcohol? As
    10·1 answer
  • A container of acetylene gas (C2H2) holds 3.86mol of acetylene and has a volume of 39.2L. If there were a leak and the volume we
    11·2 answers
  • Need this asap , help please
    5·1 answer
  • Substances A, B, and C can all act as oxidizing agents. In solution, A is green, B is yellow, and C is red. In the reactions in
    5·1 answer
  • How many moles of Fe(OH)3 are produced when 85.0 L of iron(3) sulfate at a concentration of 0.600 mol/L reacts with excess NaOH
    11·1 answer
  • Identify the charges = Mg2+ F1
    8·1 answer
  • How many moles are present in 1.2L of a 0.1 M NaCl solution?
    13·1 answer
  • What’s the answer to this? Pls help
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!