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2 years ago

What is the percentage composition of each element in Fe(OH)3

Chemistry

1 answer:

Bezzdna [24]2 years ago

3 0

Answer:

Fe =52.2%, O = 44.9%, H = 2.81%

Explanation:

Percentage composition is also known as percentage by mass.

First, find the Mr of the compound.

Mr of Fe(OH)₃ = 55.8 + (16 × 3) + (1 × 3)

= 106.8

Now Divide the mass of the element, as per the compound, by the Mr of the compound found and times that by 100.

% composition of Fe = $\frac{55.8}{106.8}$ × 100 = 52.2%

% composition of O = $\frac{16*3}{106.8}$ × 100 = 44.9%

[There are 3 oxygen atoms in the compound Fe(OH)₃, so we will multiply the atomic mass of oxygen with the number of atoms in the compound: 16×3 ]

% composition of H = $\frac{1*3}{106.8}$ × 100 = 2.81%

[There are 3 hydrogen atoms in the compound Fe(OH)₃, so we will multiply the atomic mass of hydrogen with the number of atoms in the compound: 1×3 ]

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