Question

An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is . The balloon is then taken outside, where the temperature is . Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly . Be sure your answer has the correct number of significant digits.

Answer 1

The question is incomplete, here is a complete question.

An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is 13 ⁰C. The balloon is then taken outside, where the temperature is -9 ⁰C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Be sure your answer has the correct number of significant digits.

Answer : The new volume of the balloon is 25.7 L

Explanation :

Charles's Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

$V\propto T$

or,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1$ = initial volume of gas = 27.8 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $13^oC=273+13=286K$

$T_2$ = final temperature of gas = $-9^oC=273+(-9)=264K$

Now put all the given values in the above equation, we get:

$\frac{27.8L}{286K}=\frac{V_2}{264K}$

$V_2=25.7L$

Therefore, the new volume of the balloon is 25.7 L