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lubasha [3.4K]
3 years ago
9

Robert has pure samples of both D-ribose and D-arabinose, but he forgot to label them. He only has some nitric acid, the reagent

s for a Wohl degradation, and a polarimeter (an instrument for measuring optical activity) in his lab. In approximately 50 words or less, explain how Robert can determine which sample is which without using any additional resources. If it is not possible, clearly state so and explain why it is not possible in approximately 50 words or less.
Chemistry
1 answer:
Sauron [17]3 years ago
4 0

Answer:

Following are the responses to the given question:

Explanation:

Since HN03 is an oxidation substance D-ribose u.ith oxidized to form in rubric acid Ribose is chiral, but rubric acid is achiral because of its symmetry mirror level, Hence no infrared roster in the sample holder is observed.

Please find the attached file.

D-Arabinose, on either hand, gives optical aldaric acid with such a net optical rotation observed inside the polarimeter for diagnosis with HN03.

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Determine whether each of the following statements about sulfur oxide and/or nitrogen oxide pollution is true or false.
astraxan [27]

Answer:

a) False

b) False

c) True

Explanation:

a) Most sulfur oxides formed during combustion come from sulfur in the air: The sulfur burns in presence of oxygen to produce sulfur oxides, the source of sulfur is anthropogenic activities (Human activities).

So the given statement is false.

b) A flue gas scrubber removes SO2 pollution in a coal-fired power plant by using lime to convert the SO2 into alcohols:

False

The lime reacts with sulfur dioxide to give carbon dioxide and calcium sulfite.

CaCO_{3}+SO_{2}--->CaSO_{3}+CO_{2}

c) True

c)

3 0
3 years ago
How many grams are in 44.8 liters of nitrogen gas, n2?<br> a) 56g<br> b) 27g<br> c) 36g<br> d) 112g
kkurt [141]

a) 56g

<h3>Calculation:</h3>

At STP,

22.4 L of N₂ = 1 mol

We have given 44.8 L of N₂, therefore,

44.8 L of N₂ = \frac{44.8}{22.4}

                    = 2 mol

We know that,

1 mol of N₂ = 28 g

Hence,

2 mol of N₂ = 28 × 2

                   = 56g

Hence, there are 56 g of N₂ in 44.8 L of nitrogen gas.

Learn more about calculation at STP here:

brainly.com/question/9509278

#SPJ4

3 0
2 years ago
Read 2 more answers
How does a phenol red-containing solution look if co2 level is low?
vampirchik [111]

Answer:

The variables to be examined in relation to carbon dioxide use are the amount of light exposure and amount of dissolved CO2. Phenol red is yellow/orange under acidic conditions, that is when the pH of the solution is less than 7 (e.g. pH = 6). This occurs when the concentration of CO2 is high.

Explanation:

is this correct

4 0
3 years ago
Draw the Lewis structure (including all lone pair electrons and any formal charges) for one of the four possible isomers of C3H9
Alexus [3.1K]

Answer and Explanation

The isomer picked is the N-Propylamine.

It has a lone pair of electron available on the electron rich Nitrogen and no formal charge.

Since it will be hard to draw the Lewis structure in this answer format, I'll attach a picture of the Lewis structure to this answer.

The lone pair of electron is shown by the two dots on the Nitrogen atom.

6 0
2 years ago
The density of ammonia gas under certain conditions is 0.625 g/l. calculate its density in g/cm3.
MatroZZZ [7]
From the conversion of units:
1 cm^3 is equivalent to 1 mL
1 L is equivalent to 1000 mL
therefore,
to convert from liter to cm^3, we simply multiply by 1000.
Note that the multiplication will be done in the denominator.

Based on this:
density = (0.625 g/l) x (1g/1000 cm^3) = <span> 0.000625 g/cm^3 
            = 6.25 x 10^-4 g/cm^3</span>
6 0
3 years ago
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