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lubasha [3.4K]
3 years ago
9

Robert has pure samples of both D-ribose and D-arabinose, but he forgot to label them. He only has some nitric acid, the reagent

s for a Wohl degradation, and a polarimeter (an instrument for measuring optical activity) in his lab. In approximately 50 words or less, explain how Robert can determine which sample is which without using any additional resources. If it is not possible, clearly state so and explain why it is not possible in approximately 50 words or less.
Chemistry
1 answer:
Sauron [17]3 years ago
4 0

Answer:

Following are the responses to the given question:

Explanation:

Since HN03 is an oxidation substance D-ribose u.ith oxidized to form in rubric acid Ribose is chiral, but rubric acid is achiral because of its symmetry mirror level, Hence no infrared roster in the sample holder is observed.

Please find the attached file.

D-Arabinose, on either hand, gives optical aldaric acid with such a net optical rotation observed inside the polarimeter for diagnosis with HN03.

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Answer:

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Explanation:

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3 years ago
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A water bath in a physical chemistry lab is 1.75 m long, 0.730 m wide, and 0.650 m deep. If it is filled to within 2.27 inches f
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It is 0.720 meters cause if the manufacturers of liters contain 2.27 inches it would make a deeply filled of 0.660
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A solution is made by mixing 55.g of thiophene C4H4S and 65.g of acetyl bromide CH3COBr.
EleoNora [17]

Answer:

Mole fraction of C₄H₄S = 0.55

Explanation:

Mole fraction is moles of solute / Total moles

Total moles are the sum of moles of solute + moles of solvent.

Let's find out the moles of our solute and our solvent.

Mass of solute: 55g

Mass of solvent: 65g

Mol = Mass / molar mass

55 g / 84.06 g/mol = 0.654 moles of C₄H₄S

65 g /123 g/mol = 0.529 moles of C₂H₃BrO

Total moles = 0.654 + 0.529 = 1.183 moles

Mole fraction of thiophene = Moles of tiophene / Total moles

0.654 / 1.183 = 0.55

4 0
3 years ago
What are the names of the stable forms of oxygen?
zloy xaker [14]

Answer:

18 O, 17 O, and 16 O

Explanation:

three naturally stable isotopes

5 0
2 years ago
Determine the empirical formula of a
k0ka [10]

Answer:

AuCl

Explanation:

Given parameters:

Mass of Gold  = 2.6444g

Mass of Chlorine  = 0.476g

Unknown:

Empirical formula  = ?

Solution:

Empirical formula is the simplest formula of a compound. Here is the way of determining this formula.

Elements                                     Au                                             Cl

Mass                                         2.6444                                     0.476

Molar mass                                 197                                          35.5

Number of moles                  2.6444/197                                 0.476/35.5

                                                 0.013                                           0.013

Divide by the

smallest                                 0.013/0.013                                 0.013/0.013

                                                       1                                                   1

The empirical formula of the compound is AuCl

3 0
2 years ago
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