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eduard
3 years ago
10

Is the point (1,3) a solution to the linear equation 5x-9y=32? explain

Mathematics
2 answers:
murzikaleks [220]3 years ago
4 0
5x-9y=32
P (1,3)
Substitute:
5*(1)-9*(3)=32
5-27=32
-22=32 which is impossible.
Then the point (1,3) is not a solution.
harina [27]3 years ago
3 0

There are many ways to check if the point (1,3) is a solution to the linear equation 5x-9y=32.

Let us check it by expressing y in terms of x.

The given expression is 5x-9y=32. If we add -5x to both sides we will get:

-9y=-5x+32

Multiplying both sides by -1 we will get:

9y=5x-32

In order to isolate y, we will divide both sides by 9 to get:

y=\frac{5}{9}x-\frac{32}{9}

Now let us plug in the given value of x=1 from the point (1,3). This should give us y=3. Let us see if we get y=3 when we plug x=1 in the above equation.

y=\frac{5}{9}\times 1-\frac{32}{9}=\frac{5-32}{9}

\therefore y=\frac{-27}{9}=-3

Thus, we see that when x=1, y=-3 and that y\neq 3 and hence we conclude that the point (1,3) is not a solution to the original given linear equation 5x-9y=32.

For a better understanding of the explanation given here a graph has been attached. As can be seen from the graph, (1,3) does not lie on the straight line that represents 5x-9y=32, but (1,-3) does lie on it as we had just found out.





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F(5) if f(x) = 3x - 2​
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Answer:

f(5)=12

Step-by-step explanation:

Replace all x by 5

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multiply 3 and 5 together

f(5)=15-2

Simplify:

f(5)=13

Hope this helps!

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Answer:

c=7.07

Step-by-step explanation:

c²=a²+b²

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c²=25+25

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B. c=7.07 (to nearest hundredth)

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3 0
2 years ago
Find the equation for the line that passes through the point (1,-3) and that is parallel to the line with the equation 3/2x-2y=-
kondaur [170]

The equation for the line that passes through the point (1,-3) and that is parallel to the line with the equation \frac{3}{2}x - 2y = \frac{-17}{2} is:

y = \frac{3}{4}x - \frac{15}{4}

<h3><u>Solution:</u></h3>

Given that line that passes through the point (1, -3) and that is parallel to the line with the equation \frac{3}{2}x - 2y = \frac{-17}{2}

We have to find equation of line

<em><u>The slope intercept form is given as:</u></em>

y = mx + c

Where "m" is the slope of line and "c" is the y-intercept

Let us first find slope of line containing equation \frac{3}{2}x - 2y = \frac{-17}{2}

\frac{3}{2}x - 2y = \frac{-17}{2}

Rearrange the above equation into slope intercept form

\frac{3x}{2} + \frac{17}{2} = 2y\\\\y = \frac{3x}{4} + \frac{17}{4}

On comparing the above equation with slope intercept form y = mx + c,

m = \frac{3}{4}

So the slope of line containing equation \frac{3}{2}x - 2y = \frac{-17}{2} is m = \frac{3}{4}

We know that slopes of parallel lines are equal

So the slope of line parallel to line having above equation is also m = \frac{3}{4}

<em><u>Now let us find the equation of line having slope m = 3/4 and passes through point (1 , -3)</u></em>

Substitute m = \frac{3}{4} and (x, y) = (1 , -3) in slope intercept form

y = mx + c

-3 = \frac{3}{4}(1) + c\\\\c = -3 - \frac{3}{4}\\\\c = \frac{-15}{4}

<em><u>Thus the required equation of line is:</u></em>

substitute m = \frac{3}{4} and c = \frac{-15}{4} in slope intercept form

y = \frac{3}{4}x + \frac{-15}{4}\\\\y =\frac{3}{4}x - \frac{15}{4}

Thus the equation of line is found out

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Answer:

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Step-by-step explanation:

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#2 and #3

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