All categories

3 years ago

A number cube with the numbers 1 to 6 is rolled. What is the theoretical probability of rolling the number 3?

Mathematics

2 answers:

Vinvika [58]3 years ago

8 0

Answer:

1/6

Step-by-step explanation:

When we roll a die, we can get the numbers 1,2,3,4,5,6

Each is equally likely

P(3) = How many times 3 occurs/ total

3 occurs 1 time in on the die and there are 6 possible numbers

P(3) = 1/6

mr_godi [17]3 years ago

4 0

<h3>Answer:</h3>

$\frac{1}{6}$

<h3>Step-by-step explanation:</h3>

There are 6 possible options: $\text{1, 2, 3, 4, 5, 6}$

There is 1 option out of those 6 that we are finding: $\text{3}$

Therefore, the probability is $\frac{1}{6}$ .

You might be interested in

I need help. due in 15

Andru [333]

Decimal: 0.143

Percent: 14.3%

4 0

3 years ago

Help me ASAP please

Fofino [41]

Answer:

it is .42 how I know is because I looked at the graph

Step-by-step explanation:

first I look at the school side

next I look at the car and get rid of it because it says middle school

then I get rid of bus and other

6 0

3 years ago

Read 2 more answers

Classify the following triangle

s2008m [1.1K]

Answer:

B and C

Step-by-step explanation:

It has different angles and an obtuse angle.

Have a nice day!!!!!!!! :-)

5 0

3 years ago

Allie has 3 pairs of white socks, 5 pairs of blue socks, and 2 pairs of pink socks. Wade has 8 pairs of white socks, 1 pair of b

Helen [10]

3 more. The color doesn't matter at all. It's all about the amount.

6 0

3 years ago

Read 2 more answers

Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

3 0

3 years ago