Expanding the limit, we get (x^2+2x∆x+∆x^2-2x-2∆x+1-x^2+2x-1)/<span>∆x
Crossing the 1s , the 2xs, and the x^2s out, we get
(2x</span>∆x+∆x^2-2∆x)/<span>∆x
Dividing the </span><span>∆x, we get
2x+</span><span>∆x-2.
Making the limit of </span><span>∆x=0, we get 2x-2.</span>
Ans(1):
Given equation is f(x)=-1.5x+6
we can plug any number like x=0 and x=2 to find the f(x) also called y-value
plug x=0
f(x)=-1.5x+6 =-1.5*0+6 =0+6 =6
Hence first point is (0,6)
plug x=2
f(x)=-1.5x+6 =-1.5*2+6 =-3+6 =3
Hence first point is (2,3)
now we can graph both points then join them to get final graph of f(x)=-1.5x+6
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Ans(2):
We can repeat exactly same process for f(x) = -1/2x-5.
So the final graph will look like attached picture:
What are you looking for on youre paper what letter
So (f-g)(x) = 3x2 + x, so when x = 2, the function is 14