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3 years ago

PRE-CAL/CAL MASTER NEEDED

Mathematics

1 answer:

Tanzania [10]3 years ago

3 0

For every x you see in the f function you will replace with the h function

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Which confidence level would produce the widest interval when estimating the mean of a population based on the mean and standard

Maru [420]

Answer:

D. 90%

Step-by-step explanation:

it is within the 90th percentile

8 0

3 years ago

Four times the cube of a number is less than the difference between forty and the number. Select the inequality that represents

tigry1 [53]

<u>Answer:</u>

$4x^3 < 40 - x$

<u>Explanation:</u>

let the number be x, now we are given that four times the cube of a number which means four multiplied by the cube of number

i.e 4 multiplied by $x^3$ is less than the difference of 40 and the number x i.e 40 - x

x is for sure less than 40 as $x^3$ is less than the difference between 40 and x so if we write x - 40 then we will obtain negative value which will be greater than $x^3$ .

So, the inequality obtained can be written as $4x^3 < 40 - x$

6 0

3 years ago

Read 2 more answers

Fine the exact distance between the line 6x-y=-3 and the point (6,2). Show your work. Explain your answer.

AVprozaik [17]

Answer:

$\sqrt{37}$ units

Step-by-step explanation:

If we draw a perpendicular from point (6,2) on the line 6x - y = - 3, then we have to find the length of the perpendicular.

We know the formula of length of perpendicular from a point $(x_{1}, y_{1} )$ to the straight line ax + by + c = 0 is given by

$\frac{|ax_{1} + by_{1} +c |}{\sqrt{a^{2}+b^{2}}}$

Therefore, in our case the perpendicular distance is

$\frac{|6(6)-2+3|}{\sqrt{6^{2} +(-1)^{2} } } = \frac{37}{\sqrt{37} } = \sqrt{37}$ units. (Answer)

6 0

4 years ago

Karen has $600. She spent $240 on clothes. What percentage of money did she have left?

Rudiy27

Answer: She had 60% of the money left

Step-by-step explanation:

240/600=0.4

0.4 = 40%

100%-40%=60%

7 0

3 years ago

Read 2 more answers

WHAT IS THE REMAINDER WHEN <img src="https://tex.z-dn.net/?f=32%5E%7B37%5E%7B32%7D%20%7D" id="TexFormula1" title="32^{37^{32} }"

Feliz [49]

Recall Euler's theorem: if $\gcd(a,n) = 1$ , then

$a^{\phi(n)} \equiv 1 \pmod n$

where $\phi$ is Euler's totient function.

We have $\gcd(9,32) = 1$ - in fact, $\gcd(9,32^k)=1$ for any $k\in\Bbb N$ since $9=3^2$ and $32=2^5$ share no common divisors - as well as $\phi(9) = 6$ .

Now,

$37^{32} = (1 + 36)^{32} \\\\ ~~~~~~~~ = 1 + 36c_1 + 36^2c_2 + 36^3c_3+\cdots+36^{32}c_{32} \\\\ ~~~~~~~~ = 1 + 6 \left(6c_1 + 6^3c_2 + 6^5c_3 + \cdots + 6^{63}c_{32}\right) \\\\ \implies 32^{37^{32}} = 32^{1 + 6(\cdots)} = 32\cdot\left(32^{(\cdots)}\right)^6$

where the $c_i$ are positive integer coefficients from the binomial expansion. By Euler's theorem,

$\left(32^{(\cdots)\right)^6 \equiv 1 \pmod9$

so that

$32^{37^{32}} \equiv 32\cdot1 \equiv \boxed{5} \pmod9$

7 0

2 years ago