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3 years ago

Solve this inequality for x 81 -1 1/5r <55

2 answers:

7 0

$81-1\dfrac{1}{5}r < 55\qquad|\text{subtract 81 from both sides}\\\\-\dfrac{1\cdot5+1}{5}r < -26\qquad|\text{change the signs}\\\\\dfrac{6}{5}r > 26\qquad|\text{multiply both sides by 5}\\\\6r > 130\qquad|\text{divide both sides by 6}\\\\r > \dfrac{130}{6}\\\\r > \dfrac{65}{3}\to r > 21\dfrac{2}{3}$

Jobisdone [24]3 years ago

6 0

The answer would be d thats how it was on my test

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Subtracting two different negative numbers result in a difference that is

murzikaleks [220]

Answer:

A, because when you add a positive to a negative it will always be substraction, and 2 negatives make a positive.

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A box contains 12 transistors, 3 of which are defective. If 3 are selected at random, find the probability that

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I guess your are selecting them without replacement, if so:

a) P(picking one defective) = 3/12
P(picking a 2nd defective) = 2/11
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P(1 and 2 and 3 defective) = 3/12 x 2/11 x 1/10 = 1/220 = 0.0045

b) None defective: P( Non Defective) = 9/12 (follow Same logic):
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Second method using combination:

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B) ⁹C3 / ¹²C³ = 21/55 = 0.38

5 0

3 years ago

Find the area of the segment

Alex

Answer:

Step-by-step explanation:

radius = 32 inches

angle = 60 degrees

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3 years ago

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Which polygon appears to be regular?

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The polygon that appears to be regular is Figure B the parallelogram

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3 years ago

A certain restaurant offers 6 kinds of cheese and 2 kinds of fruit for its dessert platter. If each dessert platter contains an

max2010maxim [7]

<h3>27 different dessert platters can be offered by restaurant</h3>

Solution:

Given that,

A certain restaurant offers 6 kinds of cheese and 2 kinds of fruit for its dessert platter

Each dessert platter contains an equal number of kinds of cheese and kinds of fruit

For this problem there are two scenarios:

1 ) one cheese and one fruit

2 ) two cheese and two fruit

For one cheese and one fruit

$6C_1 \times 2C_1$

Use the combination formula

$C(n, r) = \frac{n !}{r ! (n-r) ! }$

Where, n is total items and r is the items being chosen at a time

$6C_1 \times 2C_1 = \frac{ 6 ! }{ 1 ! (6 - 1) ! } \times \frac{ 2 ! }{ 1 ! ( 2 -1 ) ! }\\\\6C_1 \times 2C_1 = \frac{ 6 ! }{ 1 ! 5 ! } \times \frac{ 2 ! }{ 1 ! 1 ! }\\\\6C_1 \times 2C_1 = \frac{ 6 \times 5 \times 4 \times 3 \times 2 \times 1}{ 5 \times 4 \times 3 \times 2 \times 1} \times 2 \times 1\\\\6C_1 \times 2C_1 = 6 \times 2 = 12$

For 2 cheese and 2 fruits

$6C_2 \times 2C_2$

$6C_2 \times 2C_2 = \frac{ 6 ! }{ 2 ! ( 6 - 2) ! } \times 2C_2\\\\We\ know\ that\ 2C_2 = 1\\\\6C_2 \times 2C_2 = \frac{ 6 ! }{ 2 ! ( 6 - 2) ! } \times 1\\\\6C_2 \times 2C_2 = \frac{ 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{2 \times 1 \times 4 \times 3 \times 2 \times 1 }\\\\6C_2 \times 2C_2 = 15$

So, total ways = 12 + 15 = 27

Thus, 27 different dessert platters can be offered by restaurant

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4 years ago