All categories

3 years ago

Solve this inequality for x 81 -1 1/5r <55

2 answers:

7 0

$81-1\dfrac{1}{5}r < 55\qquad|\text{subtract 81 from both sides}\\\\-\dfrac{1\cdot5+1}{5}r < -26\qquad|\text{change the signs}\\\\\dfrac{6}{5}r > 26\qquad|\text{multiply both sides by 5}\\\\6r > 130\qquad|\text{divide both sides by 6}\\\\r > \dfrac{130}{6}\\\\r > \dfrac{65}{3}\to r > 21\dfrac{2}{3}$

Jobisdone [24]3 years ago

6 0

The answer would be d thats how it was on my test

You might be interested in

Antonio finished the race in 28 minutes and 11.00 seconds. Julio finished 0.08 second faster than Antonio. Pete finished 0.1 sec

max2010maxim [7]

Answer:

It took Peter 28 minutes and 10.82 seconds to finish the race.

Step-by-step explanation:

We have that:

$t_{A}$ : Antonio = 28 min + 11.00 s (1)

$t_{J}$ : Julio = A - 0.08 s (2)

$t_{P}$ : Pete = J - 0.1 s (3)

Then, the time at which Pete finished the race is:

$t_{P} = t_{J} - 0.1$ (4)

By entering equations (1), (2), (3) into (4) we have:

$t_{P} = (t_{A} - 0.08) - 0.1$

$t_{P} = 28 min + 11.00 s - 0.18 s = 28 min + 10.82 s$

Therefore, it took Peter 28 minutes and 10.82 seconds to finish the race.

I hope it helps you!

5 0

3 years ago

If shape 1 is similar to shape Il and shape II is similar to shape III, what does that mean for shape I and shape III?

blagie [28]

Answer:

Step-by-step explanation:

They are also similar.

Both have 4 right angles. Both have 2 sets of parallel lines. Both have 4 equal sides.

But I think you are supposed to answer if figure 1 is similar to figure 2 and figure two is similar to figure 3 then by the transitive property, figure 1 is similar to figure 3.

7 0

3 years ago

Need help ASAP!! Write an informal proof to show triangles ABC and DEF are similar.

yaroslaw [1]

Answer:

Δ ABC and Δ DEF are similar because their corresponding sides are proportional

Step-by-step explanation:

Two triangles are similar if their corresponding sides are proportional which means the corresponding sides have equal ratios

In the two triangles ABC and DEF

∵ AB = 4 units

∵ DE = 2 units

∴ $\frac{AB}{DE}=\frac{4}{2}=2$

∵ BC = 6 units

∵ EF = 3 units

∴ $\frac{BC}{EF}=\frac{6}{3}=2$

∵ CA = 2 units

∵ FD = 1 units

∴ $\frac{CA}{FD}=\frac{2}{1}=2$

∴ $\frac{AB}{DE}=\frac{BC}{EF}=\frac{CA}{FD}=2$

∵ All the ratios of the corresponding sides are equal

∴ The corresponding sides of the two triangles are proportional

∴ Δ ABC is similar to Δ DEF

6 0

3 years ago

A group of students investigated the effect of temperature of vinegar on its reaction time with baking soda. To minimize the ran

worty [1.4K]

Answer:

ehifhidbviasbeoifoaweilbfjwBFUWGUF

Step-by-step explanation:

next time you answer someone's question with a bunch of random letters just to get the points don't. It rude especially sense you have questions you want answered. Now I could be nice and help you because I know how to solve this and you obviously don't, but I'm giving you the same curtesy as you did me and writing a bunch of gibberish.

8 0

3 years ago

What types of solutions does 6x^2 - 20x + 1 have?

elena55 [62]

Answer:

2 real solutions

Step-by-step explanation:

We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:

b² - 4ac

If b² - 4ac > 0, then there are 2 real solutions. If b² - 4ac = 0, then there is 1 real solution. If b² - 4ac < 0, then there are 2 imaginary solutions.

Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:

b² - 4ac

(-20)² - 4 * 6 * 1 = 400 - 24 = 376

Since 376 is clearly greater than 0, we know this quadratic has 2 real solutions.

<em>~ an aesthetics lover</em>

3 0

3 years ago