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3 years ago

(brainiest)Which letter would be the most meaningful variable for this problem situation?

Mathematics

1 answer:

dexar [7]3 years ago

7 0

Answer:

options B

Step-by-step explanation:

because its refer to height it's denoted by (h)

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6/11 divided by 2/5

kow [346]

$\frac{6}{11} \div \frac{2}{5} = \frac{6}{11} \times \frac{5}{2} = \frac{3 \times 5}{11} = \frac{15}{11}$

7 0

3 years ago

Read 2 more answers

Please help ASAP!!??

valentina_108 [34]

Answer:

yes the table graph represents the same function

Step-by-step explanation:

6 0

2 years ago

There are 6 and 2 over 3pounds of walnuts in a container, which will be divided equally into containers that hold 1 and 1 over 3

kodGreya [7K]

6 2/3 divided equally into containers holding 1 1/3 would be 1 1/3 + 1 1/3 + 1 1/3 + 1 1/3+ 1 1/3= 6 2/3. That would fill five containers with none leftover.

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4 years ago

The service life of a battery used in a cardiac pacemaker is assumed to be normally distributed. A random sample of ten batterie

Fittoniya [83]

Answer:

The confidence interval is $25.16 < \mu < 26.85$

Step-by-step explanation:

From the question we are given a data set

25.5, 26.1, 26.8, 23.2, 24.2, 28.4, 25.0, 27.8, 27.3, and 25.7.

The mean of the this sample data is

$\= x = \frac{\sum x_i}{n}$

where is the sample size with values n = 10

$\= x = \frac{25.5+ 26.1+ 26.8+23.2+ 24.2+ 28.4+ 25.0+ 27.8+ 27.3+ 25.7}{10}$

$\= x = 26$

The standard deviation is evaluated as

$\sigma = \sqrt{\frac{\sum (x-\= x)}{n} }$

substituting values

$= \sqrt{\frac{ ( 25.5-26)^2, (26.1-26)^2, (26.8-26)^2, (23.2-26)^2}{10} }$

$\cdot \ \cdot \ \cdot \sqrt{\frac{ ( 24.2-26)^2, (28.4-26)^2+( 25.0-26)^2+ (27.8-26)^2+( 27.3-26)^2+( 25.7-26)^2}{10} }$

$\sigma = 1.625$

The confidence level is given as 90% hence the level of significance is calculated as

$\alpha = 100 -90$

$\alpha =10$ %

$\alpha = 0.10$

Now the critical values of $\frac{\alpha }{2}$ is obtained from the normal distribution table as

$Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining the critical values of $\frac{\alpha }{2}$ instead of $\alpha$ is because we are considering two tails of the area under the normal curve