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4 years ago

Please help me with these rotation problem.

Mathematics

1 answer:

FrozenT [24]4 years ago

3 0

Answer:

see below

Step-by-step explanation:

In the attachment, the points are listed in the order given in the problem statement. (They are listed to the right of the "rotation matrix", with x-coordinates above y-coordinates.)

I really don't like to do repetitive calculations, so I try to use a graphing calculator or spreadsheet whenever possible. Angles are measured CCW.

As always, the rotation transformations are ...

180° — (x, y) ⇒ (-x, -y)

270° — (x, y) ⇒ (y, -x)

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Help please!!! what goes in the y for the output?

Mazyrski [523]

Answer:

5, 2, 1, 2, 5

Step-by-step explanation:

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2 years ago

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HELLPP. ITS URGENT.50 PTS

ICE Princess25 [194]

Answer:

4x² - 13x + 8 = 0
4x² - 11x + 5 = 0
16x² - 41x + 1 = 0
x² + 5x + 4 = 0
x² - 66x + 64 = 0

Step-by-step explanation:

Given

α and β are roots of 4x²-5x-1=0

Then the sum and product of the roots are:

α+b = -(-5)/4 = 5/4
αβ = -1/4

(i) Roots are α + 1 and β + 1, then we have:

(x - (α + 1))(x - (β + 1)) = 0
(x - α - 1)(x - β - 1) = 0
x² - (α+β+2)x + α+β+ αβ + 1 = 0
x² - (5/4+2)x +5/4 - 1/4 + 1 = 0
x² - 13/4x + 2= 0
4x² - 13x + 8 = 0

(ii) Roots are 2 - α and 2 - β, then we have:

(x + α - 2)(x + β - 2) = 0
x² + (a + β - 4)x - 2(α + β) + αβ + 4 = 0
x² + (5/4 - 4)x - 2(5/4) - 1/4 + 4 = 0
x² - 11/4x - 10/4 - 1/4 + 16/4 = 0
x² - 11/4x + 5/4x = 0
4x² - 11x + 5 = 0

(iii) Roots are α² and β², then:

(x - α²)(x-β²) = 0
x² -(α²+β²)x + (αβ)² = 0
x² - ((α+β)² - 2αβ)x + (-1/4)² = 0
x² - ((5/4)² -2(-1/4))x + 1/16 = 0
x² - ( 25/16 + 1/2)x + 1/16 = 0
x² - 33/16x + 1/16 = 0
16x² - 33x + 1 = 0

(iv) Roots are 1/α and 1/β, then:

(x - 1/α)(x - 1/β) = 0
x² - (1/α+1/β)x + 1/αβ = 0
x² - ((α+β)/αβ)x + 1/αβ = 0
x² - (5/4)/(-1/4)x - 1/(-1/4) = 0
x² + 5x + 4 = 0

(v) Roots are 2/α² and 2/β², then:

(x - 2/α²)(x - 2/β²) = 0
x² - (2/α² + 2/β²)x + 4/(αβ)² = 0
x² - 2((α+β)² - 2αβ)/(αβ)²)x + 4/(αβ)² = 0
x² - 2((5/4)² - 2(-1/4))/(-1/4)²x + 4/(-1/4)² = 0
x² - 2(25/16 + 8/16)/(1/16)x + 4(16) = 0
x² - 2(33)x + 64 = 0
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3 years ago

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Will 2/5+√3 be rational or irrational? Why?

Mars2501 [29]

Answer:

Step-by-step explanation:

2/5 is a rational number and square root of 3 is irrational

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3 years ago

A water tank in the shape of an inverted circular cone has a base radius of 3 m and height of 7 m . If water is being pumped int

Wittaler [7]

The water level increases by 0.608 meters per minute when the water is 3.5 m deep

<h3>How to determine the rate?</h3>

The given parameters are:

Radius, r = 3
Height, h = 7
Rate in, V' = 4.3m^3/min

The relationship between the radius and height is:

r/h = 3/7

Make r the subject

r = 3h/7

The volume of a cone is;

$V = \frac 13\pi r^2h$

This gives

$V = \frac 13\pi (\frac{3h}{7})^2h$

Expand

$V = \frac{3h^3}{49}\pi$

Differentiate

$V' = \frac{9h^2}{49}\pi h'$

Make h' the subject

$h' = \frac{49}{9\pi h^2}V'$

When the water level is 3.5.

We have:

$h' = \frac{49}{9\pi * 3.5^2}V'$

Also, we have:

V' = 4.3

So, the equation becomes

$h' = \frac{49}{9\pi * 3.5^2} * 4.3$

Evaluate the products

$h' = \frac{210.7}{346.36}$

Evaluate the quotient

h' = 0.608

Hence, the water level increases by 0.608 meters per minute

Please help me with these rotation problem.​

Please help me with these rotation problem.