Answer:
s = 23.72 m
v = 21.56 m/s²
Explanation:
given
time to reach the ground (t) = 2.2 second
we know that
a) s = u t + 0.5 g t²
u = 0 m/s
g = 9.8 m/s²
s = 0 + 0.5 × 9.8 × 2.2²
s = 23.72 m
b) impact velocity
v = √(2gh)
v = √(2× 9.8 × 23.72)
v = √464.912
v = 21.56 m/s²
Nacl is the answer hahahahaah ha
Between the stars' absolute magnitudes<span> or </span>luminosities<span> versus their </span>stellar classifications<span> or </span>effective temperatures<span>. </span>
<span>Velocities are vectors so we can add them!
Let's let +x be East and -x be West.
-0.9 + 2.7 = 1.8
Since our answer is positive that means East so the answer is C.</span>
c.charge due to the reaction process between the two
