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Mashcka [7]
3 years ago
10

If we decrease the amount of force applied to an object, and all other factors remain the same, the amount of work completed wil

l
Physics
1 answer:
Nat2105 [25]3 years ago
4 0
A ) decrease.
B ) increase.
C ) increase, then decrease.
D ) not change.

The answer is A) decrease

Take pushing a box, for example-- You  push your hardest then give out, still trying to push the box. You are doing less work than what you have started with!

( Mind marking me for branliest? ; ) )
You might be interested in
An unknown source plays a pitch of middle C (262 Hz). How fast would the sound wave from this source have to travel to raise
Viefleur [7K]

Answer:

The sound travels at v_{s}=11.4 \mathrm{m} / \mathrm{s}

Option: c

Explanation:

Unknown source plays of middle C (fs) = 262 Hz

The sound wave from this source have to travel to raise the pitch to C sharp is (fd) = 272 Hz

\begin{array}{l}{velocity of sound in air(v)=343 \mathrm{m} / \mathrm{s}, f_{\mathrm{s}}=262 \mathrm{Hz}, f_{\mathrm{d}}=271 \mathrm{Hz}} \\ {velocity of receiver(v_{\mathrm{d}})=0 \mathrm{m} / \mathrm{s},velocity of source( v_{\mathrm{s}}) \text { is unknown }}\end{array}

\text { Speed of sound } \mathrm{V}_{\mathrm{S}}=343 \mathrm{m} / \mathrm{s}

f_{\mathrm{d}}=f_{\mathrm{s}}\left(\frac{v-v_{\mathrm{d}}}{v-v_{\mathrm{s}}}\right)

\frac{f_{d}}{f_{s}}=\left(\frac{v-v_{d}}{v-v_{s}}\right)

\left(v-v_{s}\right)=\frac{f_{s}}{f_{d}}\left(v-v_{d}\right)

v_{s}=v-\frac{f_{s}}{f_{d}}\left(v-v_{d}\right)

Substitute the given values in the formula,

v_{s}=343+\frac{262}{271}(343-0)

v_{s}=343+0.966(343)

v_{s}=343-331.33

v_{s}=11.4 \mathrm{m} / \mathrm{s}

Therefore, The sound travels at v_{s}=11.4 \mathrm{m} / \mathrm{s}

4 0
3 years ago
I feel dvmb for asking this question but... help? Please?
VMariaS [17]

<u>Force</u>, it can speed up or slow down an object which can change the direction in which an object is moving.

8 0
3 years ago
When the fission of uranium-235 is carried out, about 0.1 percent of the mass of the reactants is lost during the reaction.
Dmitry [639]

The lost mass is converted into energy.


7 0
3 years ago
A charge of 0.20uC is 30cm from a point charge of 3.0uC in vacuum. what work is required to bring the 0.2uC charge 18cm closer t
vlada-n [284]

Answer:

The correct answer is "4.49\times 10^{10} \ joules".

Explanation:

According to the question,

The work will be:

⇒ Work=-\frac{kQq}{R}

              =-\frac{1}{4 \pi \varepsilon \times (18-30)\times 3\times 0.2}

              =-\frac{1}{4 \pi \varepsilon \times (-12)\times 3\times 0.2}

              =\frac{0.3978}{\varepsilon }

              =4.49\times 10^{10} \ joules

Thus the above is the correct answer.    

3 0
3 years ago
Please give me the real answer!! ​
erica [24]
Uhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
3 0
3 years ago
Read 2 more answers
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