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Mashcka [7]
3 years ago
10

If we decrease the amount of force applied to an object, and all other factors remain the same, the amount of work completed wil

l
Physics
1 answer:
Nat2105 [25]3 years ago
4 0
A ) decrease.
B ) increase.
C ) increase, then decrease.
D ) not change.

The answer is A) decrease

Take pushing a box, for example-- You  push your hardest then give out, still trying to push the box. You are doing less work than what you have started with!

( Mind marking me for branliest? ; ) )
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A metallic wire has a diameter of 4.12mm. When the current in the wire is 8.00A, the drift velocity is 5.40×10−5m/s.What is the
podryga [215]

Answer:

6.9\times 10^{28}m^{-3}

Explanation:

We are given that

Diameter of wire=d=4.12 mm

Radius of wire=rr=\frac{d}{2}=\frac{4.12}{2}=2.06mm=2.06\times 10^{-3} m

1mm=10^{-3} m

Current=I=8 A

Drift velocity=v_d=5.4\times 10^{-5} m/s

We have to find the density of free electrons in the metal

We know that

Density of electron=n=\frac{I}{v_deA}

Using the formula

Density of free electrons=\frac{8}{5.4\times 10^{-5}\times 1.6\times 10^{-19}\times 3.14\times (2.06\times 10^{-3})^2}

By using Area of wire=\pi r^2

\pi=3.14\\e=1.6\times 10^{-19} C

Density of free electrons=6.9\times 10^{28}m^{-3}

3 0
3 years ago
Read 2 more answers
An iron sphere of radius 0.18m has mass 190 kg. Calculate the density of the iron
Slav-nsk [51]
  • radius=r=0.18m

Volume:-

\\ \sf\rightarrowtail \dfrac{4}{3}\pi r^3

\\ \sf\rightarrowtail \dfrac{4}{3}\pi (0.18)^3

\\ \sf\rightarrowtail \dfrac{4}{3}\pi (0.005832)

\\ \sf\rightarrowtail 0.024m^3

  • Mass=190kg

Density:-

\\ \sf\rightarrowtail \dfrac{Mass}{Volume}

\\ \sf\rightarrowtail \dfrac{190}{0.024}

\\ \sf\rightarrowtail 7916.67kg/m^3

8 0
2 years ago
Electrons flowing towards south are deflected towards east by a magnetic
Jet001 [13]

Answer:

The magnetic field is upwards.

Explanation:

You have to use "Right-hand rule", but for electrons, the direction of the magnetic force should be reversed.

5 0
3 years ago
A person rides a bike with a constant velocity of 2 m/s. If his total displacement is 10 meters, for how long was he riding?
TEA [102]

Answer:

5s

Explanation:

i just know

3 0
3 years ago
A 10.00-V battery is connected between two parallel metal plates 4.00 mm apart. What is the magnitude of the electric field betw
olya-2409 [2.1K]

Answer:

2500 N/C

Explanation:

Electric Field: This can be defined as the the force per unit charge in an electric field. The S.I unit is N/C

V = E.r ....................... Equation 1

Where V = Electric potential, E = Electric Field, r = Distance between the two parallel plate,

Make E the subject of the equation,

E = V/r .................... Equation 2

Given: V = 10 V, r = 4.00 mm = (4/1000) m = 0.004 m.

Substitute into equation 2

E = 10/0.004

E = 2500 N/C

Hence the electric field = 2500 N/C

6 0
3 years ago
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