Ask question

Ask question

All categories

3 years ago

15

Emilio cay type 850 words in 17 minutes. How many words can he type in one hour?

1 answer:

Nutka1998 [239]3 years ago

3 0

Answer:

3,000 words

Step-by-step explanation:

we know that

Emilio cay type 850 words in 17 minutes

Remember that

$1\ h=60\ min$

so

using proportion

Find out how many words can Emilio type in 60 minutes (one hour)

Let

x ---> the number of words

$\frac{850}{17}\ \frac{words}{minutes} =\frac{x}{60}\ \frac{words}{minutes}\\\\x=60(850)/17\\\\x= 3,000\ words$

You might be interested in

F7gy ybygygugiyhu6thyh)g6v5yy4j5g5fbry56tf4t6t

Rudiy27

Answer:

The fish that is 1 7/10 lbs

Step-by-step explanation:

1 7/10 is greater in value than any of the others.

5 0

3 years ago

Round 82.265 to the nearest whole number

poizon [28]

$82.265\approx82$

5 0

2 years ago

Professor Williams wrote some statements on the board: 1. Newton observed an apple falling off a tree and speculated that all th

romanna [79]

I THINK ITS A THEORY HOPE THIS HELPS ;}

8 0

3 years ago

Read 2 more answers

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)

vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

$x^{\frac{2}{3}}+y^{\frac{2}{3}}=4$

We have to find the equation of tangent line to the given curve at point $(-3\sqrt3,1)$

By using implicit differentiation, differentiate w.r.t x

$\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0$

Using formula : $\frac{dx^n}{dx}=nx^{n-1}$

$\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}$

$\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}$

$\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}$

Substitute the value x= $-3\sqrt3,y=1$

Then, we get

$\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}$

$\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}$

Slope of tangent=m= $\frac{1}{\sqrt3}$

Equation of tangent line with slope m and passing through the point $(x_1,y_1)$ is given by

$y-y_1=m(x-x_1)$

Substitute the values then we get

The equation of tangent line is given by

$y-1=\frac{1}{\sqrt3}(x+3\sqrt3)$

$y-1=\frac{x}{\sqrt3}+3$

$y=\frac{x}{\sqrt3}+3+1$

$y=\frac{x}{\sqrt3}+4$

This is required equation of tangent line to the given curve at given point.

8 0

3 years ago

Find the probability of being below 514 if the mean of a normal distribution is 474 and the standard deviation is 32.

Aleonysh [2.5K]

I think it is c not sure tho

7 0

2 years ago