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Otrada [13]
3 years ago
9

A= B + 3(4 - C) B=5 C= 2 A=?

Mathematics
2 answers:
fiasKO [112]3 years ago
8 0

Answer:

11

Step-by-step explanation:

substitute all letters with the numbers

5+3(4-2)

5+3(2)

5+6

=11

Trava [24]3 years ago
7 0

Answer:

A = 11 i believe

Step-by-step explanation:

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10. On one night, a group of 9 rats carried away 45 kg of food. What is the reduced ratio of rats to food weight
GenaCL600 [577]

Answer:

Number of rats : Food weight = 1 : 5

Step-by-step explanation:

Number of rats in the group = 9

Weight of food carried away by them = 45 kg

Ratio of the number of rats and food weight = \frac{\text{Number of rats}}{\text{Weight of food carried by the rats}}

                                                                          = \frac{9}{45}

                                                                          = \frac{1\times 9}{5\times 9}

                                                                          = \frac{1}{5}

Therefore, Number of rats : Food weight = 1 : 5

4 0
3 years ago
Suppose y varies inversely with x and y=20 when x=5. Write an equation for the inverse variation.
Viktor [21]
K = 20 • 5 or 20 = k/5
4 0
3 years ago
Mia sells t-shirts from a booth at a market. She pays $30 to rent the booth. Each t-shirt costs her $1.50 and she sells them $7.
brilliants [131]
5 t'shirts is the minimum she can sell to reach her goal.
4 0
3 years ago
A chef divides 5 heads of lettuce equally among 12 salad plates. How much lettuce will be on each plate?
Jet001 [13]

Answer:

It is ...

Step-by-step explanation:

7 0
3 years ago
There are 5 blue
Minchanka [31]

Answer:

The probability of randomly picking a red candy is 1/20 and In percentage value 5%

Step-by-step explanation:

There are 5 blue candies, 6 red candies, and 9 yellow candies.

Now, Total

5 + 6 + 9 = 20 candies

Now, The probability of randomly picking a red candy is 1/20

Now, In percentage

1/20 × 100% = 5%

Thus, The probability of randomly picking a red candy is 1/20 and In percentage value 5%.

<u>-TheUnknownScientist</u>

5 0
3 years ago
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