Answer:
5
Step-by-step explanation:
Answer:
The area is 0.002m² to 3 dp
Step-by-step explanation:
This problem bothers on the mensuration of flat shapes(I.e cross sectional area of pipe ) , this time the a circle.
It requires us to look for the area of the shape
Given data
Diameter d = 5cm
Converting to mm = 5/100= 0.05m
Radius of circle r=d/2=0.05/2 =0.025mm
Given the area of the circle
A=πr²
A=3.14*0.025²
A=0.0019m²
To 3 dp we have area as 0.002m²
This is a very good visual representation. Whether it is the best, or not, depends on the purposes:
First, you can see right away where the top 25% (4th quartile) scored by looking at the right hand whisker.
Second, you get two measures of variation for the data, the range and the interquartile range. Finally, by looking at the left whisker, you can see that most of the variation comes from the bottom quartile: 3/4 of the students scored between 80 and 100, while 1/4 scored between 80 and 50.
As a teacher, I would want more detail about the bottom quartile. It might be that one student scored 50 and everyone else scored between 70 and 80. But I wouldn't need to have it graphically represented. This graph shows me that the class overall is in good shape: The median is close to 90. But there is at least one student, and up to 25 % of the class who did poorly on an exam that otherwise looks very easy.
Answer:
x = 2
Step-by-step explanation:
