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The equation representing the given statement is ~
The least number of lawns that he can cut and buy the computer is 10 lawns ~
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Total savings should be greater or equal to $ 820 in order to buy the computer,
And his total savinga is equal to ~
Money he saved + money got from cutting lawns.
let's assume the lawns cut by Tyrod be x,
Money earned by cutting lawns is equal to
- total number of lawns cut × $50
total savings is equal to ~
hence,
by solving for " x (number of lawns cut) " we get ~
Hence, the least number of lawns he has to cut is the number that is greater than 9.8, which is
Step-by-step explanation:
a = 2 + 3a + 8
a = 10 + 3a
a - 3a = 10
-2a = 10
a = -5
Answer: <em>40.5</em>
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Step-by-step explanation: If it help please thanks me!
Answer:
See photo
Step-by-step explanation:
We can fill out many of these pretty easily. Look at the picture below. (Black numbers represent what information they already gave us)
Now, for the actual math.
If a total of 46 seventh-graders were surveyed and 28 seventh-graders spent more than an hour on their phone, then that means that there would have to be 46-28=18 students that spend less than an hour on their phone.
If there are 43 total students that spend more than an hour on their phone, and 28 of those are seventh-graders, then there are 43-28=15 eighth-graders that spend more than an hour on their phone
Then, if there are 27 total eighth-graders, and 15 of those spend more than an hour, then that leaves 27-15=12 eighth-graders that spend less than an hour on their phone.
Lastly, figure out the total numbers.
There are 18 seventh-graders and 12 eighth-graders that spend less than an hour on their phone, so there is a total of 18+12 = 30 students that spend less than an hour on their phone.
There are a total of 46 seventh-graders and 27 eighth-graders that were surveyed, which is a total of 73 students surveyed.
Essentially, we are trying to find the missing constant term of
(remember that we are subtracting
due to the negative sign in front of the second term). Let's expand this to see what we can work with:


Now, we know the second term is
, so let's set the second term in the polynomial we just found equal to
:


- Divide both sides of the equation by


- Divide both sides of the equation by 2
We have found
. We know the missing constant term is
, according to the polynomial we found earlier. Thus, the missing term is:

The missing constant term is 36.