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Anna007 [38]
3 years ago
9

During the Labor Day weekend, Amy and Kathleen each ran in a race. Amy ran in a 5K and completed it in 31 minutes and 15 seconds

. Kathleen ran in a half-marathon, which is 21.1 kilometers, and completed it in 2 hours, 11 minutes, and 52.5 seconds.
Let d represent distance in kilometers, r represent the rate, and t represent time in minutes. The proportional relationship
Mathematics
2 answers:
Flura [38]3 years ago
8 0

Answer:

The relationship is rate is same.          

Step-by-step explanation:

Given : During the Labor Day weekend, Amy and Kathleen each ran in a race. Amy ran in a 5K and completed it in 31 minutes and 15 seconds. Kathleen ran in a half-marathon, which is 21.1 kilometers, and completed it in 2 hours, 11 minutes, and 52.5 seconds.

Let d represent distance in kilometers, r represent the rate, and t represent time in minutes.

To find : The proportional relationship ?

Solution :      

We know, r=\frac{d}{t}

1 hour = 60 minutes = 60 × 60 seconds

First we find the rate of both Amy and Kathleen.

Amy ran in a 5 km and completed it in 31 minutes and 15 seconds.

Rate of Amy in km/hr is given by,

r_1=\frac{5}{\frac{31}{60}+\frac{15}{60\times 60}}

r_1=\frac{5}{0.516+0.00416}

r_1=\frac{5}{0.52016}

r_1=9.6km/hr

Kathleen ran in a half-marathon, which is 21.1 kilometers, and completed it in 2 hours, 11 minutes, and 52.5 seconds.

Rate of Kathleen in km/hr is given by,

r_2=\frac{21.1}{2+\frac{11}{60}+\frac{52.5}{60\times 60}}

r_2=\frac{5}{2+0.18333+0.014583}

r_2=\frac{5}{2.197}

r_2=9.6km/hr

Both man ran at the same speed.

Therefore, The relationship is rate is same.

Novosadov [1.4K]3 years ago
4 0
Velocity=distance/time

a=5/(31*60+15)=5/1875=1/375

k=21.1/(2*3600+11*60+52.5)=21.1/7912.5=1/375

a=k

The both ran at the same speed.

(1km/375s)(3600s/h)=9.6km/h
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