Answer:
Standard error = 0.4
Step-by-step explanation:
Step 1
We find the Standard Deviation
The formula = √(x - mean)/n - 1
n = 15
Mean = 1.93 hours
= √(0- 1.93)² + (0-1.93)² +(0- 1.93)²+( 0- 1.93)²+ (1- 1.93)² + (1- 1.93)² +(1 - 1.93)² +(2 - 1.93)² + (2 - 1.93)² + (2 - 1.93)² + (2 - 1.93)² + ( 2 - 1.93)² +(4 - 1.93)² +(4 - 1.93)² + (5 - 1.93)²/15 - 1
= √(3.737777776 + 3.737777776 + 3.737777776 + 0.871111111 +0.871111111 + 0.871111111 + 0.004444444445+ 0.004444444445 + 0.004444444445 + 0.004444444445 + 0.004444444445 + 1.137777778 + 4.271111112 + 4.271111112 + 9.404444446)/15 - 1
= √2.352380952
= 1.533747356
Step 2
We find the standard error
The formula = Standard Deviation/√n
Standard deviation = 1.533747356
n = 15
= 1.533747356/√15
= 1.533747356 /3.87298334621
= 0.39601186447
Approximately = 0.4
Therefore, the standard error is 0.4
Answer:
So the distance from home plate to 2nd base is 127.279 ft
Step-by-step explanation:
I think it is right hope it helps :)
Answer:
Step-by-step explanation:
w (width) = 32/8
w = 4
p (perimeter) = 2w + 2l
p = (2 x 4) + (2 x 8)
p = 8 + 16
p = 24
Answer:
Two intervals are 63 and 75
Step-by-step explanation:
Given:
Mean of students (μ) = 69 inches
Standard deviation (σ) = 3 inches μ
Find:
Interval of heights (95%) using empirical rule
Computation:
Interval of heights (95%) using empirical rule:
⇒ μ – 2σ = 69 - 2(3)
⇒ μ – 2σ = 69 - 6
⇒ μ – 2σ = 63
⇒ μ + 2σ = 69 + 2 (3)
⇒ μ + 2σ = 69 + 6
⇒ μ + 2σ = 75
Two intervals are 63 and 75
Originally,
h = 20 m, the height of the tree trunk
d = 0.5 m, the diameter of the trunk
Because the density is 380 kg/m³, the mass of the trunk is

Answer: 1492.3 kg
After one year:
After the tree puts on a growth ring, the new diameter is
d = 0.5 + 2(4 x 10⁻³ m) = 0.508 m
The tree grows by 0.2 m, s the new height is
h = 20 + 0.2 = 20.2 m
The increase in volume is

Answer: The volume produced is 0.17 m³ (nearest hundredth)