Graph the function defined by f(x)= |-x-7|
1 answer:
Answer: The answer is the third graph, attached herewith the image.
Step-by-step explanation: The given function is
We are to select the correct graph from the given four options that is defined by the function above.
At x = 0, y = 7
and
at y = -7, y = 0.
So, the points (0, 7) and (-7, 0) satisfies the given function and hence these points must lie on the graph also.
We can see that the points (0, 7) and (-7, 0) lie only on the third graph. The image is attached with these two points plotted.
Thus, the answer is the third graph.
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Answer:
50.5 m^3
Step-by-step explanation:
Volume of pyramid = 1/3 × base area × height.
- Height: 11
- Base Dimensions: 4.3 and 3.2
Area of Base:
Next, we multiply 13.76 by 11.
- 13.76 × 11
- 151.36
Lastly, divide by 3 and round to nearest tenth.
- 151.36 ÷ 3
- 50.453333..
- ≈ 50.5
Therefore, the answer is 50.5 m^3
Answer:
c) P(270≤x≤280)=0.572
d) P(x=280)=0.091
Step-by-step explanation:
The population of bearings have a proportion p=0.90 of satisfactory thickness.
The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.
As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).
The mean of this distribution will be:
The standard deviation will be:
We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:
Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.
The mean of this sampling distribution is:
The standard deviation will be:
c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:
d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction: