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jonny [76]
4 years ago
10

When two pipes fill a pool together, they can finish in 5 hours. If one of the pipes fills half the pool then the other takes ov

er and finishes filling the pool, it will take them 18 hours. How long will it take each pipe to fill the pool if it were working alone?
Mathematics
1 answer:
Alexxandr [17]4 years ago
3 0

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

➷The answer is 18 hours.

Explanation: If you look carefully, you can see that the answer is the second condition as well. If one pipe did half, then the other pipe took over and that took 18 hours, that means that it equals one pipe filling the pool continuously by itself. :)

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

DOGE

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lisov135 [29]
By the inclusion/exclusion principle,

\mathbb P(D)=\mathbb P(A\cup B\cup C)
\mathbb P(D)=\mathbb P(A)+\mathbb P(B)+\mathbb P(C)-\bigg(\mathbb P(A\cap B)+\mathbb P(A\cap C)+\mathbb P(B\cap C)\bigg)+\mathbb P(A\cap B\cap C)
\mathbb P(D)=\dfrac14+\dfrac16+\dfrac14-\dfrac39+\dfrac1{13}
\mathbb P(D)=\dfrac{16}{39}\neq1

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3 years ago
PLEASE HELP! Is my answer correct?
Oxana [17]

We know angle P is 90 degrees because of Thales Theorem, and angle N is 60 degrees. Because the angles in a triangle have to add up to 180 degrees, angle PMN has to be 30 degrees.

Angle QMO is half of angle PMN, so it's 15 degrees. Angle MQO is equal to angle QMO because the radii make Triangle OQM isosceles, so angle MQO is 15 degrees.

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A square pyramid is shown below:
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Let Surface Area A, a the base edge and h the height:

A = a²+2a√(a²/4+h²)

h=?

pythagorean theorem:

h²=c²-a²

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h=√(8²-(.7/2)²)= 8

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Prove that the value of the expression does not depend on the variable x:
Leviafan [203]

Answer:

See below

Step-by-step explanation:

If an expression is not dependent on x, it simplified form must not contain x. To show that this is the case for (a) and (b) we need to simplify them and assess:

(a)

(x-5)(x+8)-(x+4)(x-1)=\\=x^2-5x+8x-40-x^2-4x+x+4=-36

Indeed, does not depend on x!

And (b)

x^4-(x^2-1)(x^2+1)=x^4-x^4+x^2-x^2+1=1

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8 0
3 years ago
The population of a particular type of bacteria is known to triple in 22 days. What is the daily growth rate
Paul [167]

Answer: ∛(3)

Step-by-step explanation:

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then, at day N = 3*n (where n = 0, 1, 2.....) the population will be:

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(then in day one, the population grow by a factor of 3^(1/3))

N = 2 is when n = 2/3, then:

P(2) = A*3^(2/3)

The quotient between P(2) and P(1) is equal to the growth between day one and day two, this should be the same as the growth between day zero and day one.

A*3^(2/3)/(A*3^(1/3)) = 3^( 2/3 - 1/3) = 3^(1/3)

So we found that the daily growth rate is 3^(1/3) or ∛(3)

3 0
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