Answer:
-2
Step-by-step explanation:
when x = 5, f(x) = -2
hope this helps. good luck
Answer:
ABCD is not a parallelogram
Step-by-step explanation:
Use the distance formula to determine whether ABCD below is a parallelogram. A(-3,2) B(-3,3) C (5,-3) D (-1.-5)
We have to find the length of the sides of the parallelogram using the formula below
= √(x2 - x1)² + (y2 - y1)² when given vertices (x1, y1) and (x2, y2)
For side AB
A(-3,2) B(-3,3)
= √(-3 -(-3))² + (3 -2)²
= √0² + 1²
= √1
= 1 unit
For side BC
B(-3,3) C (5,-3)
= √(5 -(-3))² + (-3 -3)²
= √8² + -6²
= √64 + 36
= √100
= 10 units
For side CD
C (5,-3) D (-1.-5)
= √(-1 - 5)² + (-5 - (-3))²
= √-6² + -2²
= √36 + 4
= √40 units
For sides AD
A(-3,2) D (-1.-5)
= √(-1 - (-3))² + (-5 -2)²
= √(2² + -7²)
= √(4 + 49)
= √53 units
A parallelogram is a quadrilateral with it's opposite sides equal
From the above calculation
Side AB ≠ CD
BC ≠ AD
Therefore, ABCD is not a parallelogram
I solved this using a scientific calculator and in radians mode since the given x's is between 0 to 2π. After substitution, the correct pairs
are:
cos(x)tan(x) – ½ = 0
→ π/6 and 5π/6
cos(π/6)tan(π/6) – ½ = 0
cos(5π/6)tan(5π/6) – ½ = 0
sec(x)cot(x) + 2 =
0 → 7π/6 and 11π/6
sec(7π/6)cot(7π/6) + 2 = 0
sec(11π/6)cot(11π/6) + 2 = 0
sin(x)cot(x) +
1/sqrt2 = 0 → 3π/4 and 5π/4
sin(3π/4)cot(3π/4) + 1/sqrt2 = 0
sin(5π/4)cot(5π/4) + 1/sqrt2 = 0
csc(x)tan(x) – 2 = 0 → π/3 and 5π/3
csc(π/3)tan(π/3) – 2 = 0
csc(5π/3)tan(5π/3) – 2 = 0
First you would have to find how many inches the sign is, then you would find the radius and then multiply that by 3.50
