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LuckyWell [14K]
3 years ago
12

Please helpppppppppppppppppp

Mathematics
1 answer:
lesantik [10]3 years ago
3 0
For this problem you’d use the Cosine function.


Since cosine is adjacent over hypotenuse you’d set the y/11.3 equal to Cos35 and use simple algebra to get y alone.

Cos35 = y/11.3
Multiply each side by 11.3 which will give you 9.3
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Answer:

The nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

Step-by-step explanation:

Given the geometric sequence

7, 14, 28, ...

We know that a geometric sequence has a constant ratio 'r' and is defined by

a_n=a_1\cdot r^{n-1}

where a₁ is the first term and r is the common ratio

Computing the ratios of all the adjacent terms

\frac{14}{7}=2,\:\quad \frac{28}{14}=2

The ratio of all the adjacent terms is the same and equal to

r=2

now substituting r = 2 and a₁ = 7 in the nth term

a_n=a_1\cdot r^{n-1}

a_n=7\cdot \:2^{n-1}

Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

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2 years ago
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Answer:

5/6 cups of sugar

Step-by-step explanation:

45 divided by 18 = 2.5

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3 0
3 years ago
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