The area is Base * Height
Area = b * h
b =12 3/4 in
h = 2 1/2 in
Area = 12.75 * 2.5 = 31.875 or 31 7/8 square inches.
Answer:
im confused as you are
Step-by-step explanation:
look so what it is saying its that theres 22 in total. 14 already have a sibling and 18 have a pet. 22-14 is 8 and 22-18 is 4. how are you supposed to find the rest of them who have both?
A = bh
A = 20(12)
A = 120
Area of the computer is 120
b would be 20
and the h would be 12
b = base
h = height
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
The perimeter of a square is 52 m. What is the area of the square ?
<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
Perimeter of a square = 52 m
4 × side = 52
side =
side = 13
So, area of square = (side)² = (13)² = 169 sq m.
<h3>The area of the square is <u>1</u><u>6</u><u>9</u><u> </u><u>s</u><u>q</u><u> </u><u>m</u>. [Answer]</h3>
Answer:
0.0052 = 0.52% probability that exactly four will end up being replaced under warranty.
Step-by-step explanation:
For each telephone, there are only two possible outcomes. Either they are replaced under warranty, or they are not. The probability of a telephone being replaced under warranty is independent of any other telephone, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
Twenty percent of all telephones of a certain type are submitted for service while under warranty. Of those, 40% are replaced.
This means that 
Company purchases ten of these telephones.
This means that 
What is the probability that exactly four will end up being replaced under warranty?
This is P(X = 4). So


0.0052 = 0.52% probability that exactly four will end up being replaced under warranty.