Since it's an ordinary deck, there are 52 cards in the deck. Assume the deck is fair.
Winning cards are spades and there 13 of those in the deck - the numbers 2 through 10 (9 if them), the three face cards (J, Q, K), and the A.
Winning cards are also aces are there four of them - one for each suit (Hearts, clubs, diamonds, spades)
However the Ace of spades is among both groups so we remove it from the last group to avoid double counting. (You could from the first, but the subtraction is a must)
So there are 13 + 4 - 1 = 16 winning cards out of the deck of 52.
Thus our probability is 16/52.
c because m is the number of minutes over 3 so you would multiply that by 0.25 and add 1.05 altogether.
1.05 is what under 3 minutes is. 0.25 times m(the number of minutes over 3) and add them.
1.05+0.25
When the diagonals of a quadrilateral are perpendicular, the area of that quadrilateral is half the product of their lengths.
.. A = (1/2)*d₁*d₂
Substituting the given information, this becomes
.. 58 in² = (1/2)*(14.5 in)*d₂
.. 2*58/14.5 in = d₂ = 8 in
The length of diagonal BD is 8 in.
Answer:
± sqrt(3)i = x
Step-by-step explanation:
0 = x^2 +3
Subtract 3 from each side
-3 =x^2 +3-3
-3 =x^2
Take the square root of each side
±sqrt(-3) = sqrt(x^2)
±sqrt(-3) = x
We can split sqrt(-3) into sqrt(3) sqrt(-1) and we know that the sqrt(-1) is i
± sqrt(3)sqrt(-1) = x
± sqrt(3)i = x