First, find how much he paid by tire.
To do so, divide what he paid by how many tires he bought like this :
240$ / 12 = 20$ per tire
Then, calculate how much he sells each tire.
To do so, start by calculating how much he paid for 3 tires:
20$ x 3 = 60$
This is the price he sells 2 tires for, therefore :
60$ / 2 = 30$
he sells his tires 30$ each.
Finally, you have to calculate the profit he made by selling 12.
We already know how much it cost, so you need to find how much money he gets selling them :
12 tires x 30$ = 360$
To find the profit, take off the amount he paid from the amount he made :
360$ - 240$ = 120$
There you go!
Answer:
bueh
Step-by-step explanation:
Answer:
$8.00
Step-by-step explanation:
The problem statement gives two relations between the prices of two kinds of tickets. These can be used to write a system of equations for the ticket prices.
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<h3>setup</h3>
Let 'a' and 'c' represent the prices of adult and children's tickets, respectively. The given relations can be expressed as ...
a - c = 1.50 . . . . . . . adult tickets are $1.50 more
175a +325c = 3512.5 . . . . . total revenue from ticket sales.
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<h3>solution</h3>
We are only interested in the price of an adult ticket, so we can eliminate c to give one equation we can solve for 'a'. Using the first equation, an expression for c is ...
c = a -1.50
Substituting that into the second equation, we have ...
175a +325(a -1.50) = 3512.50
500a -487.50 = 3512.50 . . . . . . simplify
500a = 4000 . . . . . . add 487.50
a = 8 . . . . . . . . . divide by 500
An adult ticket costs $8.
