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Likurg_2 [28]
3 years ago
12

could anyone give a simple answer? sorry if im asking so many questions, im just confused. Which table of ordered pairs represen

ts a proportional relationship? A 2-column table with 3 rows. Column 1 is labeled x with entries negative 3, negative 4, negative 5. Column 2 is labeled y with entries 3, 2, 1. A 2-column table with 3 rows. Column 1 is labeled x with entries negative 1, negative 3, negative 5. Column 2 is labeled y with entries 1, 3, 5. A 2-column table with 3 rows. Column 1 is labeled x with entries negative 2, negative 4, negative 6. Column 2 is labeled y with entries negative 5, negative 7, negative 9. A 2-column table with 3 rows. Column 1 is labeled x with entries negative 2, negative 3, negative 4. Column 2 is labeled y with entries 0, negative 1, negative 2.
Mathematics
2 answers:
Ilya [14]3 years ago
5 0
I have no clue...lol
svetoff [14.1K]3 years ago
3 0

Answer:

A 2-column table with 3 rows. Column 1 is labeled x with entries 14, 28, 42. Column 2 is labeled y with entries 2, 4, 6.

Step-by-step explanation:

A 2-column table with 3 rows. Column 1 is labeled x with entries 16, 32, 48. Column 2 is labeled y with entries 1, 2, 4.

No, as x= 4 ⇒ y =64 not 48

A 2-column table with 3 rows. Column 1 is labeled x with entries 1, 5, 6. Column 2 is labeled y with entries 5, 20, 30.

No, as x = 5 ⇒ y = 25 not 20

A 2-column table with 3 rows. Column 1 is labeled x with entries 14, 28, 42. Column 2 is labeled y with entries 2, 4, 6.

Yes, as 2*7 = 14, 4*7= 28, 6*7= 42

A 2-column table with 3 rows. Column 1 is labeled x with entries 0, 1, 3. Column 2 is labeled y with entries 25, 70, 90.

No, x = 3 ⇒ y= 25+3*45= 160 not 90

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WITCHER [35]

Answer:

the circumference is 31.4159 (or 31.42)

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3 years ago
I need answer Immediately pls!!!!!!
Illusion [34]

Given:

Total number of students = 27

Students who play basketball = 7

Student who play baseball = 18

Students who play neither sports = 7

To find:

The probability the student chosen at randomly from the class plays both basketball and base ball.

Solution:

Let the following events,

A : Student plays basketball

B : Student plays baseball

U : Union set or all students.

Then according to given information,

n(U)=27

n(A)=7

n(B)=18

n(A'\cap B')=7

We know that,

n(A\cup B)=n(U)-n(A'\cap B')

n(A\cup B)=27-7

n(A\cup B)=20

Now,

n(A\cup B)=n(A)+n(B)-n(A\cap B)

20=7+18-n(A\cap B)

n(A\cap B)=7+18-20

n(A\cap B)=25-20

n(A\cap B)=5

It means, the number of students who play both sports is 5.

The probability the student chosen at randomly from the class plays both basketball and base ball is

\text{Probability}=\dfrac{\text{Number of students who play both sports}}{\text{Total number of students}}

\text{Probability}=\dfrac{5}{27}

Therefore, the required probability is \dfrac{5}{27}.

3 0
3 years ago
Need help on this question
Aloiza [94]
I hope this helps you

4 0
3 years ago
Please help
Gnesinka [82]

Answer:

1. subtract 9 from z- z-9

2. add 9 and z - z+9

3. divide 9 by z - 9/z

4. multiply 9 by z - 9z

Step-by-step explanation:

Your welcome!

Brainliest Appreciated!

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