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Elden [556K]
3 years ago
10

How many oxygen atoms are there in 582 grams of caffeine (CH10N402, 194 g/mol)? Avogadro's Number: 1 mole = 6.02 x 1023 species

A. 2 B. 6 C. 1.81 x 1024 D. 3.61 x 1024 F None of the above
Chemistry
1 answer:
Sergeu [11.5K]3 years ago
8 0

Answer:

3.61 * 10 ²⁴atoms.

Explanation:

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

w = 582 g

m = 194 g/mol

The number of moles can be calculated from the above formula , and substituting the respective values ,

n = w / m  = 582 g / 194 g/mol  =  3 mol

In the molecular formula of caffeine ,

<u>In 1 mole of caffeine their are - 2 moles of Oxygen. </u>

Therefore , in  3 moles of Caffeine there will be 6 moles of oxygen.

As well know ,

one mole of any substance contains 6.023*10²³ atoms,

Therefore , in  6 mol of oxygen =  6 * 6.023*10²³ atoms  = 3.61 * 10 ²⁴atoms.

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A mixture containing nitrogen and hydrogen weighs 3.49 g and occupies a volume of 7.45 L at 305 K and 1.03 atm. Calculate the ma
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Mass percent N₂ = 89%

Mass percent H₂ = 11%

Explanation:

First we <u>use PV=nRT to calculate n</u>, which is the total number of moles of nitrogen and hydrogen:

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So now we know that

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and

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So we have a <u>system of two equations and two unknowns</u>. We use algebra to solve it:

Express MolH₂ in terms of MolN₂:

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  • MolH₂ = 0.307 - MolN₂

Replace that value in the second equation:

  • MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49
  • (0.307-MolN₂) * 2 + MolN₂ * 28 = 3.49
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  • 0.614 + 26MolN₂ = 3.49
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Now we calculate MolH₂:

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Mass % N₂ = 3.108/3.49 * 100% = 89.05% ≅ 89%

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