Which exponential function has an initial value of 2? f(x) = 2(3x) On a coordinate plane, an exponential function approaches y =
0 in quadrant 2 and increases into quadrant 1. It crosses the y-axis at (0, 0.5) and goes through (2, 2). f(x) = 3(2x) A 2-column table has 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f (x) with entries one-eighth, one-fourth, one-half, 1, 2.
Well i don't know if this will help but slope intercept form
y=mx+b
M-slope B-Y intercept and (x,y)- would be any point on the graph and if you were to plug those points in for x and y the equation would solve if done properly
