Which exponential function has an initial value of 2? f(x) = 2(3x) On a coordinate plane, an exponential function approaches y =

Question

3 years ago

10

Which exponential function has an initial value of 2? f(x) = 2(3x) On a coordinate plane, an exponential function approaches y =

0 in quadrant 2 and increases into quadrant 1. It crosses the y-axis at (0, 0.5) and goes through (2, 2). f(x) = 3(2x) A 2-column table has 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f (x) with entries one-eighth, one-fourth, one-half, 1, 2.

Mathematics

2 answers:

mixer [17] · Answer 1 · 2022-06-07T00:40:51+03:00

mixer [17]3 years ago

9 0

Answer:

A

Step-by-step explanation:

Katen [24] · Answer 2 · 2022-06-06T23:29:10+03:00

Katen [24]3 years ago

8 0

Answer:

The correct answer is A. f(x)= 2(3^x)

Step-by-step explanation: