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AVprozaik [17]
3 years ago
10

Which exponential function has an initial value of 2? f(x) = 2(3x) On a coordinate plane, an exponential function approaches y =

0 in quadrant 2 and increases into quadrant 1. It crosses the y-axis at (0, 0.5) and goes through (2, 2). f(x) = 3(2x) A 2-column table has 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f (x) with entries one-eighth, one-fourth, one-half, 1, 2.
Mathematics
2 answers:
mixer [17]3 years ago
9 0

Answer:

A

Step-by-step explanation:

Katen [24]3 years ago
8 0

Answer:

The correct answer is A. f(x)= 2(3^x)

Step-by-step explanation:

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Given:

Initial number of bacteria = 3000

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Solution:

Let P(t) be the number of bacteria after t number of hours.

The exponential growth model (continuously) is:

P(t)=P_0e^{kt}

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Putting P(t)=15000,P_0=3000, k=2.8 in the above formula, we get

15000=3000e^{2.8t}

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5=e^{2.8t}

Taking ln on both sides, we get

\ln 5=\ln e^{2.8t}

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\dfrac{1.609438}{2.8}=t

0.574799=t

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4 0
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Answer:

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